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Leona [35]
2 years ago
9

HELP ME PLZ I HAVE LIMITED TIME Imagine your teacher asks you to design an experiment where you test the effect of temperature o

n the growth of a plant. You have 5 plants that you plant and place in different temperatures around the room. What would your variables be and what would your constants be.
Physics
1 answer:
PilotLPTM [1.2K]2 years ago
5 0
Your variables would be varied temperature while your constants should be everything else (water, soil, proximity). Therefore, you can test for one variable (temperature difference) without muddling the results
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The distance between the first and fifth minima of a single-slit diffraction pattern is 0.500 mm with the screen 37.0 cm away fr
WARRIOR [948]
In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
y_n= \frac{n \lambda D}{a} (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
\lambda is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem, 
D=37.0 cm=0.37 m
\lambda=530 nm=5.3 \cdot 10^{-7} m
while the distance between the first and the fifth minima is
y_5-y_1 = 0.500 mm=0.5 \cdot 10^{-3} m (2)

If we use the formula to rewrite y_5, y_1, eq.(2) becomes
\frac{5 \lambda D}{a} - \frac{1 \lambda D}{a} =\frac{4 \lambda D}{a}= 0.5 \cdot 10^{-3} m
Which we can solve to find a, the width of the slit:
a= \frac{4 \lambda D}{0.5 \cdot 10^{-3} m}= \frac{4 (5.3 \cdot 10^{-7} m)(0.37 m)}{0.5 \cdot 10^{-3} m}=  1.57 \cdot 10^{-3} m=1.57 mm

7 0
3 years ago
A balloon is a sphere with a radius of 5.0 m. the force of air against the walls of the balloon is 45 n. what is the air pressur
Mazyrski [523]

The air pressure inside the balloon is: 0.1432 Pa

The formulas and procedures that we will use to solve this problem are:

  • a = 4 * π * r²
  • P = F/a

Where:

  • a = area of the sphere
  • r = radius
  • π = mathematical constant
  • P = Pressure
  • F = Force
  • a = surface area

Information about the problem:

  • r = 5.0 m
  • F = 45 N
  • 1 Pa = N/m²
  • 1 N = kg * m/s²
  • a=?
  • P=?

Using the formula of the sphere area we get:

a = 4 * π * r²

a = 4 * 3.1416 * (5.0 m)²

a = 314.16 m²

Applying the pressure formula we get:

P = F/a

P = 45 N/314.16 m²

P = 0.1432 Pa

<h3>What is pressure?</h3>

It is a physical quantity that expresses the force applied on the area of a surface.

Learn more about pressure at: brainly.com/question/26269477

#SPJ4

7 0
1 year ago
Which phrases describe all the outer planets motion? Select two options
11111nata11111 [884]

Answer:

slow revolution and  fast rotation

Explanation:

4 0
2 years ago
A steel ball and a piece of clay have equal mass. They are dropped from the same height on a horizontal steel platform. The ball
emmasim [6.3K]

Answer: The ball (option A)

Explanation: change in momentum is defined by the formulae m(v - u) where m = mass of object, v = final velocity and u = initial velocity.

For the ball, it hits the ground and bounces back with the same speed, that's final velocity equals initials (v = - u)

Change in momentum = m( -u- u) = m(-2u) = m(-2u) = -2mu

For the clay, it final velocity is zero since it sticks to the floor, hence (v =0)

m(v - u) = m(0 - u) = - mu.

-2mu (change in momentum from the ball) is greater than - mu ( change in momentum of clay)

6 0
3 years ago
The isomerization of cyclopropane to form propene is a first-order reaction. At 760 K, 85% of a sample of cyclopropane changes t
Nataliya [291]

Answer:

so rate constant  is 4.00 x 10^-4 s^{-1}

Explanation:

Given data

first-order reactions

85% of a sample

changes to propene t =  79.0 min

to find out

rate constant

solution

we know that

first order reaction are

ln [A]/[A]0 = -kt

here [A]0 = 1 and (85%) = 0.85 has change to propene

so that [A] = 1 - 0.85 = 0.15.

that why

[A] / [A]0= 0.15 / 1

[A] / [A]0 = 0.15

here t = (79) × (60s/min) = 4740 s  

so

k = - {ln[A]/[A]0} / t

k = -ln 0.15 / 4740

k = 4.00 x 10^-4 s^{-1}

so rate constant  is 4.00 x 10^-4 s^{-1}

3 0
2 years ago
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