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Novay_Z [31]
4 years ago
12

Joseph has started completing the square on the equation 3x^2 - 7x + 12 = 0. He has worked to the point where he has the express

ion x^2-7/2 x = -4. Show work to show whether or not his work is accurate.
Mathematics
1 answer:
ololo11 [35]4 years ago
3 0
3x^2 - 7x + 12 = 0...move the 12 to the other side
3x^2 - 7x = -12....now divide by 3
x^2 - 7/3x = -4..this is where he made his mistake
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Identify the sets that contain 2 as an element. (Check all that apply.)Check All That Apply{2, 3, 4, 5, ...}{2, 3, 4, 5, ...}{0,
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Question:

Identify the sets that contain 2 as an element. (Check all that apply.)

A.\ \{2, 3, 4, 5, ...\}

B.\ \{0, 1, 4, 9, ...\}

C.\ \{2, \{2\} \}

D.\ \{\{2\}, \{\{2\}\}\}

E.\ \{\{2\}, \{2, \{2\}\}\}

F.\ \{\{\{2\}\}\}

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A.\ \{2, 3, 4, 5, ...\}

C.\ \{2, \{2\} \}

Step-by-step explanation:

Required

For which of the options is 2 an element

A.\ \{2, 3, 4, 5, ...\}

The elements of this set starts from 2, then 3 and continues as thus.

Hence: 2 is an element

B.\ \{0, 1, 4, 9, ...\}

From the given elements in the above set, 2 is not listed.

Hence: 2 is not an element of this set

C.\ \{2, \{2\} \}

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Since 2 is listed as an element, then 2 is an element of the set.

D.\ \{\{2\}, \{\{2\}\}\}

Here, 2 is listed as a subset of {2} and also as a subset of subset of {{2}}.

Since 2 is not listed as an element itself, then 2 is not an element of the set.

E.\ \{\{2\}, \{2, \{2\}\}\}

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Hence: 2 is not an element of the set

F.\ \{\{\{2\}\}\}

Here, 2 is listed as a subset of subset of {{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.

Hence: 2 is not an element of the set

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