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4 years ago

10. Marvin is painting three squares shaped like

Mathematics

1 answer:

guapka [62]4 years ago

6 0

Answer:

A certain cube has a side length of 25 m. How many square tiles, each with an area of 5 m2, are needed to fully cover the surface of the cube?

Possible Answers:

500

1000

200

100

750

Correct answer:

750

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Help me solve this plz

Reptile [31]

Answer:

sorry but this photo is not clear

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3 years ago

Evaluate 3x+2 for x=2

mafiozo [28]

Answer:

Step-by-step explanation:

3(2)+2

6+2

7 0

3 years ago

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To the nearest tenth, which is the perimeter of ABC. Geometry

qwelly [4]

Answer:

23.6

Step-by-step explanation:

Finding AC:

Cos 61 = $\frac{adjacent}{hypotenuse}$

0.48 × 10 = Adjacent

AC = 4.8

Now, CB:

Cos 29 = $\frac{adjacent}{hypotenuse}$

0.87 × 10 = CB

CB = 8.8

The perimeter:

=> 10+4.8+8.8

=> 23.6

3 0

3 years ago

Read 2 more answers

Compute the matrix of partial derivatives of the following functions.

s344n2d4d5 [400]

For a vector-valued function

$\mathbf f(\mathbf x)=\mathbf f(x_1,x_2,\ldots,x_n)=(f_1(x_1,x_2,\ldots,x_n),\ldots,f_m(x_1,x_2,\ldots,x_n))$

the matrix of partial derivatives (a.k.a. the Jacobian) is the $m\times n$ matrix in which the $(i,j)$ -th entry is the derivative of $f_i$ with respect to $x_j$ :

$D\mathbf f(\mathbf x)=\begin{bmatrix}\dfrac{\partial f_1}{\partial x_1}&\dfrac{\partial f_1}{\partial x_2}&\cdots&\dfrac{\partial f_1}{\partial x_n}\\\dfrac{\partial f_2}{\partial x_1}&\dfrac{\partial f_2}{\partial x_2}&\cdots&\dfrac{\partial f_2}{\partial x_n}\\\vdots&\vdots&\ddots&\vdots\\\dfrac{\partial f_m}{\partial x_1}&\dfrac{\partial f_m}{\partial x_2}&\cdots&\dfrac{\partial f_n}{\partial x_n}\end{bmatrix}$

So we have

(a)

$D f(x,y)=\begin{bmatrix}\dfrac{\partial(e^x)}{\partial x}&\dfrac{\partial(e^x)}{\partial y}\\\dfrac{\partial(\sin(xy))}{\partial x}&\dfrac{\partial(\sin(xy))}{\partial y}\end{bmatrix}=\begin{bmatrix}e^x&0\\y\cos(xy)&x\cos(xy)\end{bmatrix}$

(b)

$D f(x,y,z)=\begin{bmatrix}\dfrac{\partial(x-y)}{\partial x}&\dfrac{\partial(x-y)}{\partial y}&\dfrac{\partial(x-y)}{\partial z}\\\dfrac{\partial(y+z)}{\partial x}&\dfrac{\partial(y+z)}{\partial y}&\dfrac{\partial(y+z)}{\partial z}\end{bmatrix}=\begin{bmatrix}1&-1&0\\0&1&1\end{bmatrix}$

(c)

$Df(x,y)=\begin{bmatrix}y&x\\1&-1\\y&x\end{bmatrix}$

(d)

$Df(x,y,z)=\begin{bmatrix}1&0&1\\0&1&0\\1&-1&0\end{bmatrix}$

5 0

3 years ago

Please help with this

Arturiano [62]

Answer:

10x^2 -4x +6

Step-by-step explanation:

The area of the blue square is

2* 5x^2 = 10x^2

The area of the pink square is

2 * -2x = -4x

The area of the green square is

2 *3 = 6

Add it all together

10x^2 -4x +6

4 0

3 years ago