The largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Step-by-step explanation:
Let the integers be:
x and x+1
The sum of these integers is less than 46
Solving and finding value of x:
So, the integers will be less than 22.5
The largest numbers are: 21 and 22
So, the largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Keywords: Finding integers
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Answer:
x = negative 1 plus-or-minus StartRoot 17 EndRoot
Step-by-step explanation:
Given:
We need to solve for x.
First we will solve L.H.S
Factorizing the equation we get;
Now Things which are equal to the same thing are also equal to one another. Since
then, according to the law of transitivity,
Now, applying the Square Root Principle we get:
Now Square root and square gets cancelled.
Since a square root has two values, one positive and the other negative.
Hence Final Answer is .
