Answer:
0.03605 V/m is the electric field in the gold wire.
Explanation:
Resistivity of the gold =
Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)
Diameter of the wire = d = 0.9 mm
Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm =
( 1mm = 0.001 m)
Area of the cross-section =
Resistance of the wire = R
Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)
( Ohm's law)
We know, Electric field is given by :
0.03605 V/m is the electric field in the gold wire.
Answer:
563712.04903 Pa
Explanation:
m = Mass of material = 3.3 kg
r = Radius of sphere = 1.25 m
v = Volume of balloon =
M = Molar mass of helium =
= Density of surrounding air =
R = Gas constant = 8.314 J/mol K
T = Temperature = 345 K
Weight of balloon + Weight of helium = Weight of air displaced
Mass of helium is 6.4356 kg
Moles of helium
Ideal gas law
The absolute pressure of the Helium gas is 563712.04903 Pa
The resultant of the two vectors is 141 km/h.
Explanation:
When two vectors are at right angles to each other, their resultant can be calculated by using the Pythagorean's theorem:
where
A is the magnitude of the first vector
B is the magnitude of the second vector
In this problem, we have two velocity vectors of magnitude
A = 100 km/h
B = 100 km/h
Substituting into the formula, we find their resultant:
Learn more about vector addition here:
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