The best answer is b) increased turbidity from erosion.
Nonpoint source pollution generally happens as a result of many systems interacting, and is not directly attributed to one event or pollutant. Generally, natural environmental systems participate in pollution of this kind, regardless of whether or not human activity was a factor. Examples include water runoff, or erosion.
The other pollutants listed have a direct cause and direct effect, the animal waste goes directly from the animals to the ground they live on, the car shop directly sumps the oil on the ground, and the oil tank leaks directly into the earth. Erosion causing turbidity is a less direct form of pollution, and is due to the synthesis of several natural phenomena<span />
Answer:
E_{k2}=2660 [J] kinetic energy.
Explanation:
The energy in the initial state i.e. when the rollercoaster is at the top is equal to the energy in the final state i.e. when it is at the bottom of the hill.
These states can be represented by means of the second equation.
![E_{k1}+E_{p1}=E_{k2}\\160 + 2500 = E_{k2}\\E_{k2}=2660 [J]](https://tex.z-dn.net/?f=E_%7Bk1%7D%2BE_%7Bp1%7D%3DE_%7Bk2%7D%5C%5C160%20%2B%202500%20%3D%20E_%7Bk2%7D%5C%5CE_%7Bk2%7D%3D2660%20%5BJ%5D)
Since the rollercoaster is located in the bottom of the hill where the potential energy level is zero, therefore there is only kinetic energy in the second state.
Answer:
Convection and Radiation mechanisms carry most of the heat
Explanation:
This is because Convection proceeds strongy as heated air rises from the hot element while Radiation is also strong, although the material of the cooking pots will how effective it is.
Answer:
The value is 
Explanation:
Generally the thermal efficiency is mathematically represented as

substituting [ 627°C + 273 = 900K ] for
and [ 90°C + 273 = 333K ] for 
So

=> 
Explanation:
It is given that,
When the front wheels are over the scale, the weight recorded by the scale is 5800 N, F₁ = 5800 N
When the rear wheels are over the scale, the scale reads 6500 N, F₂ = 6500
The distance between the front and rear wheels is measured to be 3.20 m, x₂ = 3.2 m
We need to find the location of center of mass behind the front wheels. Let the center of is located at a distance of x₁. Thus balancing the torques we get :

On solving the above equation we get, x₂ = 1.69 m
So, the center of mass is located at a distance of 1.69 meters behind the front wheels.