Answer:
n_cladding = 1.4764
Explanation:
We are told that θ_max = 5 °
Thus;
θ_max + θ_c = 90°
θ_c = 90° - θ_max
θ_c = 90° - 5°
θ_c = 85°
Now, critical angle is given by;
θ_c = sin^(-1) (n_cladding/n_core)
sin θ_c = (n_cladding/n_core)
n_cladding = (n_core) × sin θ_c
Plugging in the relevant values, we have;
n_cladding = 1.482 × sin 85
n_cladding = 1.4764
Answer:
2.6 m
Explanation:
The work done by the bird is given by
where
F is the force exerted
d is the distance covered
In this problem, we know:
is the work
is the force
Solving the equation for d, we find the distance covered by the bird:
Answer:
A. The photographer will get to the jeep before the rhinocerous
Explanation:
Δv = Δd/Δt
we can rearrange for time
Δt = Δd/Δv
For the photographer:
Distance is 10m and moves at 6m/s
Δt = 10m/6m/s
Δt = 1.67s
For the rhinocerous
Distance is 16m and moves at 8m/s
Δt = 16m/8m/s
Δt = 2.00s
The distances were to get to the jeep, the photographer makes it to the jeep in a shorter amount of time than the rhino
