Answer:

ω = 0.0347 rad/s²
a ≅ 1.07 m/s²
Explanation:
Given that:
mass of the model airplane = 0.741 kg
radius of the wire = 30.9 m
Force = 0.795 N
The torque produced by the net thrust about the center of the circle can be calculated as:

where;
F represent the magnitude of the thrust
r represent the radius of the wire
Since we have our parameters in set, the next thing to do is to replace it into the above formula;
So;


(b)
Find the angular acceleration of the airplane when it is in level flight rad/s²

where;
I = moment of inertia
ω = angular acceleration
The moment of inertia (I) can also be illustrated as:

I = ( 0.741) × (30.9)²
I = 0.741 × 954.81
I = 707.51 Kg.m²

Making angular acceleration the subject of the formula; we have;

ω = 
ω = 0.0347 rad/s²
(c)
Find the linear acceleration of the airplane tangent to its flight path.m/s²
the linear acceleration (a) can be given as:
a = ωr
a = 0.0347 × 30.9
a = 1.07223 m/s²
a ≅ 1.07 m/s²
Hey, unfortunately it’s impossible for me to draw one for you here, but you should be able to draw it yourself pretty easily!
Answer:
An atom is built with a combination of three distinct particles: electrons, protons, and neutrons. Each atom has a center nucleus, where the protons and neutrons are densely packed together. Surrounding the nucleus are a group of orbiting electrons. And here is a picture that may assist your further :
Hope this helps
Answer:
The object's maximum speed remains unchanged.
Explanation:
The speed of a particle in SHM is given by :

Maximum speed is, 
If A' = 2A and T' = 2T



So, the maximum speed of the object remains the same i.e. it remains unchanged. Hence, this is the required solution.
Kinetic energy is the energy possessed by an object on motion. it is expressed as follows:
KE = 0.5mv^2
where m is the mass and v is the velocity of the object. We calculate as follows:
KE = 0.5mv^2
1.1x10^9 J = 0.5(8.0x10^4 kg) v^2
v = 165.83 m/s