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8090 [49]
3 years ago
12

An airline allows passengers 36 kilograms of luggage . Carl has to lower the weight of his bag by 25% to stay within the limit .

How much did the suitcase weigh originally?
Mathematics
1 answer:
Vsevolod [243]3 years ago
4 0
The suit case originally weights 48 kg
.75x = 36x = 33/ .75 = 48
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Help me with this please I will give you Brainliest
oksian1 [2.3K]
Answer

h = 8.12 cm

Explanation

Area of a parallelogram = b • h

We know the area is 20.3 cm^2 and that the base is 2.5cm.

Therefore 20.3 cm^2 = 2.5h

20.3/2.5 = 8.12 cm

h = 8.12 cm
3 0
3 years ago
What is 8.05x10^-5 in standard notation
Marina CMI [18]

Answer: 0.0000805

Step-by-step explanation:

You move the decimal 5 places to the left of 8.05.

6 0
4 years ago
Which is NOT a factor of 48?<br> A.24<br> B.16<br> C.4<br> D.26
vovikov84 [41]
26
Hope this was helpful !
4 0
3 years ago
Read 2 more answers
Find the value of the missing coefficient in the factored form of 8f^3-216g^3
adoni [48]

Answer:

The value of the missing coefficient is 12

Step-by-step explanation:

* Lets explain how to factorize the difference of two cubes

- The factorization of the difference of two cubes like a³ - b³, is a

  product of a binomial and trinomial

- The binomial is the cube root of the first term and the second term

∵ The ∛a³ = a and ∛b³ = b

∴ The binomial is (a - b)

- We will find the trinomial from the binomial by square the 1st term

 of the binomial and multiply the 1st term and the 2nd term of the

 binomial with opposite sign of the binomial and square the 2nd

 term of the binomial

∴ The trinomial is (a² + ab + b²

∴ The factorization of (a³ - b³) is (a - b)(a² + ab + b²)

* Lets solve the problem

∵ 8f³ - 216g³ is the difference of two cubes

∵ ∛(8f³) = 2f

∵ ∛(216g³) = 6g

∴ The binomial is (2f - 6g)

- Lets make the trinomial

∵ (2f)² = 4f²

∵ (2f)(6g) = 12fg

∵ (6g)² = 36g²

∴ The trinomial = (4f² + 12fg + 36g²)

∴ The factorization of 8f³ - 216g³ = (2f - 6g)(4f² + 12fg + 36g²)

∴ The value of the missing coefficient is 12

7 0
3 years ago
What is the equation of the following line? Be sure to scroll down first to see
likoan [24]

\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{-1}{0+3}\implies -\cfrac{1}{3}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{-\cfrac{1}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=-\cfrac{1}{3}(x+3) \\\\\\ y-1=-\cfrac{1}{3}x-1\implies y=-\cfrac{1}{3}x

3 0
3 years ago
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