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marysya [2.9K]
3 years ago
9

Determine whether the given lengths can be sides of a triangle. HELLLLP MEEEEE GUYS ;)))

Mathematics
2 answers:
irakobra [83]3 years ago
8 0

Answer:

B

Step-by-step explanation:

7^2=49 40^2=1600 1600+49=1649 is not equal to 41^2 so its not a right triangle

12/4=3 16/4=4 20/4=5 3,4,5 is one of the combinations of a right triangle

Musya8 [376]3 years ago
5 0

Answer:

A, both can be sides of a triangle

Step-by-step explanation:

  1. you add up the lowest side lengths and see if they are more than the largest side length
  2. if they are then they can be side lengths
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Answer:

KJM and KJH

Step-by-step explanation:

Supplementary angles are angles that equal 180 degrees

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X/7=3/2 solve equation, check solution<br>​
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Answer:

Step-by-step explanation:

X/7=3/2  multiply by : 5

x = 21/2

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A function is shown in the table.
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<span>Given:
x       g(x)
−3      17
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2        13

The true statement for the given function is:
</span><span>The function is decreasing from x = −3 to x = −1.
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3 years ago
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Complete the recursive formula of the geometric sequence -0.3, 0.9, -2.7, 8.1. ....
SSSSS [86.1K]

Answer:

(-1)ⁿ(3)ⁿ/10

Step-by-step explanation:

The first term a = 0.3, the second term, ar = 0.9. The common ratio r = ar/a = 0.9/-0.3 = -3.

From the general term of a geometric series,

U = arⁿ⁻¹

= (0.3)(-3)ⁿ⁻¹

= (3/10)(-3)ⁿ⁻¹

= (-1)ⁿ⁻¹(3)(3)ⁿ⁻¹/10

= (-1)ⁿ(3)ⁿ/10

5 0
3 years ago
A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s
Greeley [361]

Using a system of equations, it is found that:

  • For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
  • For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
  • For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

--------------------

The variables of the system are:

  • x, which is the number of $29 tickets sold.
  • y, which is the number of $34 tickets sold.

Total of 8,000 seats, all can be sold, thus:

x + y = 8000 \rightarrow x = 8000 - y

--------------------

For a profit of $255,000, we have that:

29x + 34y = 255000

29(8000 - y) + 34y = 255000

5y = 23000

y = \frac{23000}{5}

y = 4600

x = 8000 - 4600 = 3400

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.

--------------------

For a profit of $271,000, we have that:

29x + 34y = 271000

29(8000 - y) + 34y = 271000

5y = 39000

y = \frac{39000}{5}

y = 7800

x = 8000 - 7800= 200

For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.

--------------------

For a profit of $235,000, we have that:

29x + 34y = 235000

29(8000 - y) + 34y = 235000

5y = 3000

y = \frac{3000}{5}

y = 600

x = 8000 - 600 = 7400

For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

A similar problem is given at brainly.com/question/22826010

3 0
3 years ago
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