This looks like an exercise that's building toward the idea of a derivative.
These calculations are done best with a calculator, but here's how the first interval is used:
Average velocity = (position at 2 - position at 1) / (2 - 1) It's really distance divided by time!
Position at t = 2:
Position at t = 1:
So over the interval [1, 2] the average velocity is
I used a spreadsheet to calculate the average velocity over the other intervals and a couple of shorter ones, too. (See attached image.)
As these intervals get shorter (the right endpoint is approaching 1), the average velocity gets closer and closer to the instantaneous velocity. An estimate would be -12.6.
answer
c
Step-by-step explanation:
because, u add them and then divide by 3 and that is ur answer
Answer: 195 mm
Step-by-step explanation: You multiply 19.5 by 10 because you need to find out how many milimeters are in 19.5 cm,
Answer:
The value of a₂₇ is 294
Step-by-step explanation:
a₁₃ = 254
a₃₃ = 654
Now,
a₁₃ = 254 can be written as
a + 12d = 254 ...(1) and
a₃₃ = 654 can be written as
a + 32d = 654 ...(2)
Now, from equation (2) we get,
a + 32d = 654
a + 12d + 20d = 654
254 + 20d = 654 (.°. a + 12d = 254)
20d = 654 - 254
20d = 400
d = 400 ÷ 20
d = 20
Now, for the value of a put the value of d = 20 in equation (1)
a + 12d = 254
a + 12(20) = 254
a + 240 = 254
a = 254 - 240
a = 14
Now, For a₂₇
a₂₇ = a + 26d
a₂₇ = 14 + 9(20)
a₂₇ = 14 + 180
a₂₇ = 294
Thus, The value of a₂₇ is 294
<u>-TheUnknownScientist</u>
Evaluate int[sin^3(θ)cos(θ)dθ] with u = sin(θ)
du/dθ = cos(θ), dθ = du/cos(θ)
The integral becomes:
int[u^3•cos(θ)du/cos(θ)]
= int[u^3•du]
= u^4/4 + C
Substitute u = sin(θ) to get back a function of θ:
sin^4(θ)/4 + C