Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= 
But this distance needs to be betweem 50 & 60
So

Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= 
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
Answer:
78
Step-by-step explanation:
Normal division
7488\96=78
Answer: 9+4n-1 = 20
We can solve this by substitution.
Replace n with the value given, 3 (remember 4n means 4 times n):
9 + 4*3 - 1
Then work it out using arithmetic
9+12-1
=20
D.
(-4v*3v) + (-4v*-5) + (3v*7) + (7*-5)
-12v^2 + 20v + 21v -35
-12v^2 + 41v -35
Points that are given on x+y=4 are (0,4),(3,1) and (4,0) and points that are give for x-y=2 are (0,-2),(2,0) and (3,1)