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2 years ago

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The number of miles USC employees commute to campus is normally distributed. To estimate the mean of this distribution, four emp

loyees were sampled. They had a mean commute of 10 miles and a standard deviation of 2 miles. What is the margin of error for the 90 percent confidence interval for the population mean? Round your answer to three decimal places.

1 answer:

Aleksandr [31]2 years ago

7 0

Yfiyfidy. It’s soot ioydotdi

It’s Bc. H. Dey h. Yes so I’m hehe what crazy now

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Using appropriate properties find: 2/3 × 3/4 + 3/7 × 3/4

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$\frac{23}{28}$

Step-by-step explanation:

$\frac{2}{3} \times \frac{3}{4} + \frac{3}{7} \times \frac{3}{4}$

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2 years ago

Becky went scuba diving. The inequality statement compares the magnitude of two depths that she reached.

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Step-by-step explanation:

Becky went scuba diving. The inequality statement compares the magnitude of two depths that she reached.

1-28] > 1-3

What does the inequality statement show?

Select from the drop-down menus to correctly complete the statement.

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3 years ago

f a storm window has an area of 400 square inches, what are the dimensions if the window is 12 inches wider than it is high (w x

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2 years ago

Read 2 more answers

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

a

The estimate is $- 0.0265\le K \le 0.0465$

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

3 0

2 years ago