Answer: P(G even and W>2) = 1/3 or 0.333 or 33.3%
Step-by-step explanation:
Independent events multiply probabilities,
P(G even)=1/2, P(W>2)=2/3, P(G even and W>2)= 1/2 × 2/3 = 1/3.
Without using definition of "independent events", or rules referring to them, I use sample space S of 36 points, and P(event) = #(event)/#(sample space).
Points are labeled with two digits, left is green die, right is white die. S = {11,12,13,14,15,16,21,...26,...,61,...,66}, and #(S)=36.
An event E is a subset of S, and
0 <= #(E) <= #(S) = 36.
Event G even is GE={21,22,23...,41,42,...,61,...,66},
#(G even)=18
Event "W>2" = W2 ={13,14,15,16,23,24...,63,64,65,66},
#(W>2)=24.
Event G even and W>2 GEW2={23,24,25,26,43,44,45,46,63,64,65,66),
#(GEW2)=12
P(GEW2)=#(GEW2)/#(S)=12/36=1/3=33.3%
