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Elenna [48]
4 years ago
12

The drawing below (not to scale) shows a running track. The ends are semicircles. The distance between the two inner parallel st

raight lines is 60 meters, and they are each 100 meters long. The track is 10 meters wide. Find the area of the actual track (the shaded region).

Mathematics
1 answer:
Nostrana [21]4 years ago
3 0
First we calculate the area of each semicircle (half the area of the full circle)
and we substract them to get the area of the curved shaded part

1/2 * [ pi * (80/2)**2 ] - 1/2 * [ pi * (60/2)**2 ] = (800-450)pi = 350*pi m2

the area of the full circle   (both sides) ------------2*350*pi m2--750*pi m2

The area of the straight line = 2 * (100 *10) = 2000 m2

Total Area = 2000 +700*pi m2 = 4198 m2
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jenyasd209 [6]

Answer:

The equilibrium quantity is 26.4

Step-by-step explanation:

Given

Q_d = 48 - 9P

Q_s = 12 + 6P

Required

Determine the equilibrium quantity

First, we need to determine the equilibrium by equating Qd to Qs

i.e.

Q_d = Q_s

This gives:

48 -9P = 12 + 6P

Collect Like Terms

-9P - 6P = 12 - 48

-15P = -36

Solve for P

P = \frac{-36}{-15}

P =2.4

This is the equilibrium price.

Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:

Q_d = 48 - 9P

Q_d = 48 - 9 * 2.4

Q_d = 26.4

<em>Hence, the equilibrium quantity is 26.4</em>

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3 years ago
I need help asp . I'm running out of time​
frutty [35]

Answer:

A = 104 ft²

Step-by-step explanation:

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3 years ago
By what percent will a fraction increase if its numerator is increased by 60% and its denominator is decreased by 20%?
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Lets just use \frac{10}{20} for an example. If the number is increased by 60% and the denominator is decreased by 20% we get the new fraction being: \frac{16}{16}. Since then new one is equal to 1, and the original is equal to \frac{1}{2}, we see that this manipulation of the fraction causes an increase of 100%. 
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3 years ago
2y-4x=10 solve for x
Rzqust [24]

Answer:

down below :)

Step-by-step explanation:

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3 years ago
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Answer:

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3 years ago
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