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PSYCHO15rus [73]
3 years ago
15

2) Solve the linear equation 2(3x + 2) = 2x - 1+x

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0
Solving for x right?
2) 6x + 4 = 3x - 1
6x - 3x = -1 - 4
3x = -5
x = - 5/3

3) x - 9 = 3/5x
5(x-9) = 3x
5x - 45 = 3x
2x = 45
x = 45/2
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Solve for x.<br><br> x3=125<br><br> Enter your answer in the box.<br><br> x =
olchik [2.2K]

Answer:

x = 5

Step-by-step explanation:

 =(-5-√-75)/2=(-5-5i√ 3 )/2= -2.5000-4.3301i

x =(-5+√-75)/2=(-5+5i√ 3 )/2= -2.5000+4.3301i

x = 5

source tiger-algebra.com

4 0
3 years ago
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The arithmetic sequence a; is defined by the formula:
Morgarella [4.7K]

Answer:

The sum of the first 650 terms of the given arithmetic sequence is 2,322,775

Step-by-step explanation:

The first term here is 4

while the nth term would be ai = a(i-1) + 11

Kindly note that i and 1 are subscript of a

Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula

Sn = n/2[2a + (n-1)d)

Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.

Plugging these values, we have

Sn = (650/2) (2(4) + (650-1)11)

Sn = 325(8 + 7,139)

Sn = 325(7,147)

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3 years ago
Solve for x: 27 ^ (x + 1) = 9 ^ x​
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Which of the following is a complex number? (Look at picture)
schepotkina [342]

Answer:

B.

Step-by-step explanation:

In mathematics, a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a symbol, called the imaginary unit, that satisfies the equation i² = −1. Because no real number satisfies this equation, i was called an imaginary number by René Descartes.

3 0
2 years ago
Write -4i+(1/4-5i)-(-3/4+8i)+17i as a complex number in the standard for
KatRina [158]

Answer:

1+ 0i

Step-by-step explanation:

A complex number is a number which has some real part and some imaginary part.

Standard form of a complex number is represented as

a +bi

Where a is the real part,

and bi is the imaginary part.

And i = \sqrt{-1}

Given complex number:

-4i+\dfrac{1}{4}-5i)-(-\dfrac{3}{4}+8i)+17i\\\Rightarrow -4i+\dfrac{1}{4}-5i + \dfrac{3}{4}-8i+17i\\\Rightarrow  \dfrac{3}{4}+\dfrac{1}{4}-4i -5i-8i+17i\\\Rightarrow  \dfrac{3+1}{4}-17i+17i\\\Rightarrow \dfrac{4}{4}+0i\\\Rightarrow 1 + 0i

Hence, the standard form is 1+ 0i.

8 0
3 years ago
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