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jeka94
3 years ago
11

An ostrich run 6 mile in12 minut how far he could come in 40 minutes

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

The ostrich can run 20 miles in 40 minutes.

<u>Solution:</u>

Given that, An ostrich run 6 mile in 12 minutes

We have to find how far he could come in 40 minutes

Now, according to the given information  

Ostrich runs 6 miles ⇒ 12 minutes

Then, “n” miles ⇒ 40 minutes

Now, by criss cross multiplication we get,

\begin{array}{l}{\rightarrow 6 \times 40=n \times 12} \\\\ {\rightarrow 40=n \times 2} \\\\ {\rightarrow n=20}\end{array}

Hence, the ostrich can run 20 miles in 40 minutes

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A function rule takes an input, and converts it into an output, y, by decreasing twice the input by 4. what is the output for th
Harman [31]

Answer:

  • when the input = 4
  • Then the output = 6

Step-by-step explanation:

It is stated that a function rule takes an input, and converts it into an output, y, by decreasing twice the input by 4.

Let 'x' be the number

Decreasing twice the number 'x' by 4 = 2x-4

Now,

Given the input x = 5

As the output will decrease twice the input (x=5) by 4

Thus, the output = 2(5)-4 = 10-4 = 6

Therefore,

  • when the input = 4
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3 years ago
6b^3 (2a+7b), how to solve it?
slamgirl [31]
<span>6b^3 (2a+7b)

</span>
<span><span>(<span>6b^3</span>)</span><span>(<span>2a+7b</span><span>)

</span></span></span>
<span><span><span>=(<span>6b^3</span>)</span><span>(2a)</span></span>+<span><span>(<span>6b^3</span>)</span><span>(7b)

</span></span></span>
<span><span>=12ab^3</span>+<span>42<span>b^4]



Answer:  </span></span></span>
<span><span><span>12a</span><span>b^3</span></span>+<span>42<span>b^4</span></span></span>    
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3 years ago
What's the distance between (0,2) and (0,8)?
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Answer:

6 units

Step-by-step explanation:

The distance between two points can be calculated with the formula

\boxed{\textcolor{steelblue}{\text{Distance between 2 points}= \sqrt{(y_1 - y_2)^{2} + (x_1 - x_2)^{2}  } }}

However, since (0, 2) and (0, 8) have the same x coordinate of 0, the distance between them is the difference in their y-coordinates.

Distance between (0, 2) and (0, 8)

= 8 -2

= 6 units

7 0
2 years ago
What is this word phrase as a math expression?
Arlecino [84]

11 times the sun of a number and 15

11(y+15)

the answer is d

have great day and I hope you make a good grade

3 0
2 years ago
Read 2 more answers
Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.
dsp73

Answer:

The required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, a_2=10,a_3=5,a_4=2.5,a_5=1.25

r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}

The common ratio of GP is 1/2.

r=\frac{a_2}{a_1}

\frac{1}{2}=\frac{10}{a_1}

a_1=20

The first term of the sequence is 20.

The formula for sequence is

a_n=a(r)^{n-1}

Where a is first term and r is common difference.

The required sequence is

a_n=20(\frac{1}{2})^{n-1}

The formula for rate of change is

m=\frac{f(x_2)-f(x_1)}{x_2-x_1}

The average rate of change from n = 1 to n = 3 is

m=\frac{f(3)-f(1)}{3-1}

m=\frac{5-20}{3-1}

m=\frac{-15}{2}=-7.5

Therefore the required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

8 0
3 years ago
Read 2 more answers
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