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Lesechka [4]
3 years ago
8

A 45-45-90 triangle has a hypotenuse of length 7. What is the length of one of its legs? If necessary, round your answer to two

decimal places.
Mathematics
1 answer:
harkovskaia [24]3 years ago
4 0
If the legs are legnth x, then the hyptonuse is x√2

x√2=7
divide both sides by √2
x=7/√2
times (√2)/(√2)
(7√2)/2
3.5√2
aprox 4.94974
round
4.95
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= > x + \frac{1}{3} = 9



\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}



= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}




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Does anyone know any 7th grade math? cus i really need help with this.
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