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Dvinal [7]
2 years ago
5

Identify the slope and y-intercept of the function y=-11x+6

Mathematics
1 answer:
ASHA 777 [7]2 years ago
7 0

Answer:

the slope is 11 and the y intercept is 6

y = mx + b

m= 11

b= 6

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(6x - 3) - (-3x + 2)
nadezda [96]

Answer:

Step-by-step explanation:

Simplifying

6x + -3 = (3x + -2)

Reorder the terms:

-3 + 6x = (3x + -2)

Reorder the terms:

-3 + 6x = (-2 + 3x)

Remove parenthesis around (-2 + 3x)

-3 + 6x = -2 + 3x

Solving

-3 + 6x = -2 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

-3 + 6x + -3x = -2 + 3x + -3x

Combine like terms: 6x + -3x = 3x

-3 + 3x = -2 + 3x + -3x

Combine like terms: 3x + -3x = 0

-3 + 3x = -2 + 0

-3 + 3x = -2

Add '3' to each side of the equation.

-3 + 3 + 3x = -2 + 3

Combine like terms: -3 + 3 = 0

0 + 3x = -2 + 3

3x = -2 + 3

Combine like terms: -2 + 3 = 1

3x = 1

Divide each side by '3'.

x = 0.3333333333

Simplifying

x = 0.3333333333

6 0
2 years ago
Find the quotient and any excluded values.<br><br> (x + 5/x^2 + 9x + 20)/(x^2-16/x-4)
Wittaler [7]
By  <span>(x + 5/x^2 + 9x + 20) you apparently meant the following:

         x+5
 ----------------------
   x^2 + 9x + 20

and by 

</span><span>(x^2-16/x-4)
                                       x^2-16
you apparently meant ---------------
                                         x - 4

Please use additional parentheses for clarity.

Dividing,

</span>         x+5                   (x-4)(x+4)
 ----------------------  *  ---------------
   x^2 + 9x + 20                  x-4

Now, x^2 + 9x + 20 factors into   (x+4)(x+5), so what we have now is

       (x+5)(x+4)
------------------------- = 1           This is true for all x, so there are no exclusions.
    (x+4)(x+5)
3 0
3 years ago
Please help <br>is this a function or not ​
JulsSmile [24]
It’s not a function cause the x is repeating
8 0
3 years ago
Read 2 more answers
Which of the following graphs shows the solution set for the inequality below? 3|x + 1| &lt; 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
2 years ago
what is the largest and smallest number of the people that could have been there and what is it rounded to the nearest thousand
Luda [366]
I really don't know that sweetly try someone else
4 0
3 years ago
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