Combining the like-terms, the result of the addition of polynomials f(x) and g(x) is given by:
<h3>How do we add polynomials?</h3>
We add polynomials combining the like-terms, that is, adding terms with the same exponent.
In this problem, the polynomials are:
Combining the like terms, the addition is given by:
More can be learned about addition of polynomials at brainly.com/question/9438778
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Answer:
The exponential model for the population is 
Step-by-step explanation:
The exponential model for the population has the following format:
In which P(0) is the initial population and r is the growth rate, as a decimal.
A population numbers 19,000 organisms initially and grows by 4.8% each year.
This means that 
So
The exponential model for the population is
Answer:
The number pattern is that the decimal point moves one place to the left each time.
Next three numbers: 7.3456, 0.73456, 0.073456
Step-by-step explanation:
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
