Answer:
Step-by-step explanation:
(3,1) lies below the vertex, so the parabola opens downwards.
Equation for a down-opening parabola with vertex (2,3):
y = a(x-2)² + 3, a<0
Plug in (3,1) and solve for a:
1 = a1² + 3
a = -2
y = -2(x-2)² + 3
so confusing i really need help with this math
Answer:
The correct options are;
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A
Step-by-step explanation:
Here we have for City A
Maximum - Minimum = 10
Interquartile range =3
City B
Maximum - Minimum = 18.5
Interquartile range =9.5
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.
Hello.
C) x=4π/3
The variable x in the cotangent argument has a unit coefficient, so the period is π, just as it is in the parent function cot(x).
Can you graph y = cot(x)? By subtracting the constant π/6 from the argument, that graph is translated to the right by π/6. Just as with cot(x), it is decreasing everywhere.
Have a nice day
Given:
ft and 
ft.
To find:
The value of P.
Solution:
We have,
Substituting and , we get
Taking LCM, we get
Therefore, the value of P is 
ft.
