<u>Stomach</u> is the part of the GI tract does not actively participate in the digestion of carbohydrates.
Carbohydrates are first mechanically and chemically broken down in the mouth. Mastication, another term for chewing, breaks down the meals high in carbohydrates into ever-tinier bits. Saliva that covers the food particles is produced by salivary glands in the mouth cavity. Salivary amylase is an enzyme found in saliva.
Dietary carbohydrates are converted to glucose, fructose, and/or galactose in the small intestine and then absorbed into the blood. The breakdown and absorption of dietary carbohydrates can be influenced by a variety of factors.
The given question is incomplete, find below the complete question,
Q. Which part of the GI tract does NOT actively digest carbohydrates?
a)small intestine
b)stomach
c)pancreas
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Answer:
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Explanation:
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Answer:
a. Bands at 1kb, 6kb and 8kb
Explanation:
The EcoRI and BamHI are the restriction enzymes which cut the DNA sequence especially a plasmid at specific sites called the restriction sites.
The restriction enzymes produces bands of specific length therefore these restriction enzymes are used to estimate the approximate length of the DNA.
In the given question, the
1. EcoRI- produces two strands of 7 kb and 8 kb
2. BamHI- produces two strands of 1kb and 14kb
This shows that the length of DNA sequence is 15kb
But when the DNA strand are digested with both the enzymes simultaneously then it will produce three bands as:
i) 14 kb can be broken down in 2 bands of 6 kb and 8 kb
ii) 1 kb band is already produced by the Bam HI.
This shows that 1+6+8= 15 kb
Thus, Option-A is correct.
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