Here is the equation to find that answer A=bh+2ls+ib i got it off line if its not right im sory
I think it is 53 that’s what i would put if i were u
Isolate one variable in the system of equations. Use substitution to create a one-variable equation. Then, set the quadratic equation equal to zero and find the discriminant. If the discriminant is negative, then there are no real number solutions. If the discriminant is zero, then there is one real number solution. If the discriminant is positive, then there are two real number solutions.
is this a school qustion? if not
cool me too
<span>The correct answer is 216x</span>⁶<span>y</span>⁵<span>.
Explanation:
The first thing we do is raise the last monomial to the third power.
(4xy)(2x</span>²<span>y)(3xy)</span>³
<span>=(4xy)(2x</span>²<span>y)(3</span>³<span>x</span>³<span>y</span>³<span>)
=4xy(2x</span>²<span>y)(27x</span>³<span>y</span>³<span>).
Now we can multiply the first two monomials. When we multiply powers with the same base, we add the exponents:
8x</span>³<span>y</span>²<span>(27x</span>³<span>y</span>³<span>).
We multiply these last two monomials, again adding the exponents:
216x</span>⁶<span>y</span>⁵<span>.</span>
