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4 years ago

11

Thea builds the first layer of rectangular prism using 4 unit cubes.Raj adds 4 more layers of 4 unit cubes each. How many unit c

ubes are used for the prism?

1 answer:

pishuonlain [190]4 years ago

3 0

You simply multiply 4 by 5 and get 20. :)

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There are 12 months in a year.

erica [24]

Answer:

12 months=1 years

24 months=2 years

36 months=3 years

(click choose and pin the photo please) so that i can see options

hope it helps you

make me brainliest plz

3 0

3 years ago

I need help please please I appreciate it! ):

telo118 [61]

Answer:

!. Scale factor = 5

2. Scale factor = $\frac{1}{5}$

Step-by-step explanation:

scale = $\frac{length in drawing}{actual length}$

1. To increase the numbers, let the scale factor be $\frac{5}{1}$ = 5. So that;

0.05 x 5 = 0.25

$\frac{1}{2}$ x 5 = 0.5 x 5 = 2.50

7 x 5 = 35.00

13 x 5 = 65.00

25 x 5 = 125.00

102 x 5 = 510.00

2. To decrease the numbers, let the scale factor be $\frac{1}{5}$ . So that;

0.05 x $\frac{1}{5}$ = 0.01

$\frac{1}{2}$ x $\frac{1}{5}$ = 0.5 x $\frac{1}{5}$ = 0.10

7 x $\frac{1}{5}$ = 1.40

13 x $\frac{1}{5}$ = 2.60

25 x $\frac{1}{5}$ = 5.00

102 x $\frac{1}{5}$ = 20.40

6 0

3 years ago

The theoretical probability of landing on blue on a single spin of a spinner with 1 purple, 1 blue , 1 red , and 1 orange sectio

erik [133]

Hey there!

$\large\boxed{25\%}$

Assuming that all the sections are the same size, there are four sections of equal size.

Blue would be one out of those four sections, so the probability is 1/4. In decimal form this is .25, and as a percent this is 25%.

Hope this helps!

5 0

3 years ago

Read 2 more answers

How to calculate distance between two points (-3,2) and (3,0).<br> And pls find the radical

irina1246 [14]

√74
Explanation:
To calculate the distance use the
distance formula
d=√(x2−x1)^2+(y2−y1)^2

−−−2
where
(x1,y1)and (x2,y2)
are 2 coordinate points
The 2 points here are (-3 ,7) and (4 ,2)
let(x1,y1)=(−3,7) and (x2,y2)=
(4,2)⇒d=√(4−(−3))2+(2−7)2=√49+25=√74←in radical form

7 0

3 years ago

Read 2 more answers

The operations manager of a manufacturer of television remote controls wants to determine which batteries last the longest in hi

Margarita [4]

Answer:

$t=\frac{107.75-116.75}{\sqrt{\frac{2.75^2}{4}+\frac{9.604^2}{4}}}}=-1.802$

The degrees of freedom are given by:

$df=n_{1}+n_{2}-2=4+4-2=6$

The p value for this case would be given by:

$p_v =2*P(t_{(6)}$

Since the p value is higher than the significance level we have enough evidence to FAIl to reject the null hypothesis and we can conclude that the true mean is not significantly different between the two types of battery

Step-by-step explanation:

Information given

Battery 1 106 111 109 105

Battery 2 125 103 121 118

We can calculate the mean and the deviation with the following formulas"

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_{1}=107.75$ represent the mean for the Battery 1

$\bar X_{2}=116.75$ represent the mean for the Bettery 2

$s_{1}=2.75$ represent the sample standard deviation for the Battery 1

$s_{2}=9.604$ represent the sample standard deviation for the battery 2

$n_{1}=4$ sample size selected for the Battery 1

$n_{2}=4$ sample size selected for the Battery 2

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to check if the difference in longevity between the two batteries, the system of hypothesis would be:

Null hypothesis: $\mu_{1} = \mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

The statistic is given by:

$t=\frac{\bar X_{s1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

The statistic is given by:

$t=\frac{107.75-116.75}{\sqrt{\frac{2.75^2}{4}+\frac{9.604^2}{4}}}}=-1.802$

The degrees of freedom are given by:

$df=n_{1}+n_{2}-2=4+4-2=6$

The p value for this case would be given by:

$p_v =2*P(t_{(6)}$

Since the p value is higher than the significance level we have enough evidence to FAIl to reject the null hypothesis and we can conclude that the true mean is not significantly different between the two types of battery

8 0

3 years ago