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3 years ago

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Thea builds the first layer of rectangular prism using 4 unit cubes.Raj adds 4 more layers of 4 unit cubes each. How many unit c

ubes are used for the prism?

1 answer:

pishuonlain [190]3 years ago

3 0

You simply multiply 4 by 5 and get 20. :)

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I’ll Brainlylist to whoever gets this correct - Due today <br> Please and thank you

Mariulka [41]

Answer:

1. 0 & 2

2. 5

3. 10

4. 17

hope this helps!

4 0

1 year ago

Find the terminal point on the unit circle determined by 11pi/6 radiants

irga5000 [103]

Answer:

$(\frac{\sqrt{3}}{2},-\frac{1}{2})$

Step-by-step explanation:

The unit circle has the parametric equation:

$x=\cos \theta$

$y=\sin \theta$

where $\theta=\frac{11\pi }{6}$ in our case is the terminal side of the angle in standard position.

We substitute to get:

$x=\cos \frac{11\pi }{6}=\frac{\sqrt{3}}{2}$

$y=\sin \frac{11\pi }{6}=-\frac{1}{2}$

$\therefore (\frac{\sqrt{3}}{2},-\frac{1}{2})$ is the required point.

6 0

2 years ago

PLEASE ANSWER ASAP!! THANKS!!

Elena L [17]

Answer:

40

Step-by-step explanation:

The angles stay the same but, the position of the triangle changes.

Hope this helps,

kavitha

8 0

3 years ago

Read 2 more answers

Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

4 0

6 months ago

HIGHSCHOOL ALGEBRA!!!!! PLS HELP :) <br> Find the root of the equation: (6x–1)(6x+1) - 4x(9x+2) = −1

My name is Ann [436]

(6x–1)(6x+1) - 4x(9x+2) = −1

Simplify the left side:

36x^2-1 -36x^2-8x = -1

Combine like terms:

-1 -8x = -1

Add 1 to both sides:

-8x = 0

Divide both sides by -8:

x = 0 / -8

x = 0

The root is 0

5 0

3 years ago