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3 years ago

X - 10 = 25 please solve this hurry

Mathematics

2 answers:

Alona [7]3 years ago

4 0

X is equal to 35
Sorry I would have put x=35 but aparently you have to have 20 characters

Kitty [74]3 years ago

3 0

X - 10 = 25
add 10 to both sides
X = 35

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A car dealership has found that the length of time before a major repair is required on the new cars it sells is normally distri

weqwewe [10]

Answer:

Step-by-step explanation:

Hello!

The variable of interest in this case is:

X: length of time before a major repair is required on a new car. (months)

This variable has a normal distribution with mean μ= 36 months and a standard deviation σ= 9 months.

If he wants to set a guarantee period in which only 5% of the sold cars fell, the objective is to find the value of X that has below 5% of the cars that need major repairs before the end of the guarantee period.

Check the attachment, the curve represents the distribution of the population of the time it takes before a new car needs major repairs, I've marked approximately where this value of X should be.

Symbolically:

P(X≤a)=0.05

To reach the proper value of "a" you have to work using the standard normal distribution because is a tabulated distribution and you can extrapolate it to any normal distribution.

$Z= \frac{X-Mu}{Sigma}~N(0;1)$

So the first step is to look in the table of the Z distribution for the value that accumulates 0.05 of probability since it is such a low probability, you have to look for the value in the left side of the table (negative values of Z). You look for 0.05 in the body of the table and then the margins for the corresponding value (see second attachment)

$Z_{0.05}= -1.64$

Then the value that accumulates 0.05 of probability is -1.64, now you have to reverse the standardization to reach the asked value of X

Z= (a- μ)/σ

(Z*σ)= a - μ

a=(Z*σ)+ μ

a=(-1.64*9)+36

a= 21.24 months.

The guarantee period should be 21.24 months so that only 5% of the sold cars will need major repairs before it wears of.

I hope it helps!

5 0

3 years ago

What zodiac are u ?

Wewaii [24]

I’m a Leo august 14th!

8 0

3 years ago

Read 2 more answers

Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.

FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

$\rho = \sqrt{x^{2}+y^{2}+z^{2}}$

$\phi = cos^{-1}\frac{z}{\rho}$

For angle θ:

If x > 0 and y > 0: $\theta = tan^{-1}\frac{y}{x}$ ;

If x < 0: $\theta = \pi + tan^{-1}\frac{y}{x}$ ;
If x > 0 and y < 0: $\theta = 2\pi + tan^{-1}\frac{y}{x}$ ;

Calculating:

a) (4,2,-4)

$\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}}$ = 6

$\phi = cos^{-1}(\frac{-4}{6})$

$\phi = cos^{-1}(\frac{-2}{3})$

For θ, choose 1st option:

$\theta = tan^{-1}(\frac{2}{4})$

$\theta = tan^{-1}(\frac{1}{2})$

b) (0,8,15)

$\rho = \sqrt{0^{2}+8^{2}+(15)^{2}}$ = 17

$\phi = cos^{-1}(\frac{15}{17})$

$\theta = tan^{-1}\frac{y}{x}$

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = $\frac{\pi}{2}$

c) (√2,1,1)

$\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}}$ = 2

$\phi = cos^{-1}(\frac{1}{2})$

$\phi$ = $\frac{\pi}{3}$

$\theta = tan^{-1}\frac{1}{\sqrt{2} }$

d) (−2√3,−2,3)

$\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}}$ = 5

$\phi = cos^{-1}(\frac{3}{5})$

Since x < 0, use 2nd option:

$\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }$

$\theta = \pi + \frac{\pi}{6}$

$\theta = \frac{7\pi}{6}$

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

$r=\sqrt{x^{2}+y^{2}}$

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

$r=\sqrt{4^{2}+2^{2}}$ = $\sqrt{20}$

$\theta = tan^{-1}\frac{1}{2}$

z = -4

b) (0, 8, 15)

$r=\sqrt{0^{2}+8^{2}}$ = 8

$\theta = \frac{\pi}{2}$

z = 15

c) (√2,1,1)

$r=\sqrt{(\sqrt{2} )^{2}+1^{2}}$ = $\sqrt{3}$

$\theta = \frac{\pi}{3}$

z = 1

d) (−2√3,−2,3)

$r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}}$ = 4

$\theta = \frac{7\pi}{6}$

z = 3

5 0

3 years ago

The length of two sides of a triangle are 10, 15 find the range of possible lengths for the third side

Zepler [3.9K]

Answer:

Range for third side is

( 5 , 25 ) cm.

Step-by-step explanation:

As two sides of triangle are 10 and 15 ,

the third side would have to be less than the sum of other two sides i.e. less than 25 cm.

On the other hand if it is smaller one than this side plus side of length 10

should be greater than 15 and therefore

this side is greater than 15 − 10 = 5 cm.

Hence range is

( 5 , 25 )

Hope this answer helps you :)

Have a great day

Mark brainliest

5 0

2 years ago

The length and width of a rectangle are consecutive integers. The perimeter of the

Hunter-Best [27]

The length of the rectangle is 9 feet and the width of the rectangle is 10 feet.

<h3>What is the Perimeter of a Rectangle?</h3>

The sum of a rectangle's boundary lengths on all sides is known as its perimeter. A rectangle's perimeter is a linear measurement that can be expressed in meters, feet, inches, or yards. Let's first comprehend the two fundamental characteristics of a rectangle.

A rectangle has four 90° angles.
The lengths of a rectangle's diagonals are equal.

Let the length of the rectangle be x feet

Then, the width of the rectangle will be x+1feet

We know that the perimeter of a rectangle is given by

P= 2(l+w)

Here

P= perimeter of a rectangle

l=length of the rectangle

w= width of the rectangle

Put l=x, w= x+1 and P= 38 in the perimeter formula

38 = 2(x+x+1)

Divide both sides by 2

19= x+x+1

19= 2x+1

Subtract 1 from both sides

18=2x

Divide both sides by 2

x=9 feet

This is the length of the rectangle.

Now, the width x+1 of the rectangle will be

9+1 = 10 feet

To know more about the perimeter of a rectangle, visit:

brainly.com/question/2142493

#SPJ9

5 0

10 months ago