All categories

1 year ago

If you prove that △ABD is congruent to △CDB, which general statement best describes what you have proved?

Mathematics

1 answer:

fredd [130]1 year ago

5 0

Answer:

A: Opposite sides of a parallelogram are congruent

Step-by-step explanation:

The only diagonal involved is BD, so none of the statements regrading diagonals has been proven. The only thing proven is ...

AB ≅ CD . . . . opposite sides are congruent

AD ≅ CB . . . . opposite sides are congruent

You might be interested in

Determine whether the value is a parameter or statistic 43.87% of voters turned out for the 2004 elections

inna [77]

Answer:

5 but its probaly not right bc im just looking for pointsStep-by-step explanation:

6 0

3 years ago

Prompt<br> Describe a simulation used to determine a game of darts.

sladkih [1.3K]

Answer:

anonymous simulation

5 0

3 years ago

Questions are on the picture, a-e.

iris [78.8K]

The equilibrium price is $1.12.
If price is $0.98, there would be scarcity of Super Widgets.
When price is $0.98, quantity demanded is y.
When price is $0.98, quantity supplied is x.
When price is $1.22, there would be a surplus of Super Widgets.

<h3>What is equilibrium? </h3>

Equilibrium price is the price at which the quantity demanded equals the quantity supplied. The equilibrium price is $1.12.

Above equilibrium price, quantity supplied would exceed quantity demanded and there would be a surplus. When price is below equilibrium price, quantity supplied would be less quantity demanded and there would be a scarcity.

To learn more about equilibrium, please check: brainly.com/question/26075805

#SPJ1

5 0

1 year ago

Please help me <br>solve 3x+1/2=3/8+x

gavmur [86]

Answer:

x= - $\frac{1}{32}$

Step-by-step explanation:

First move the x on the right side the the left side. Now your equation is

2x+ $\frac{1}{2}$ = $\frac{3}{8}$ Next move 1/2 to the right side. Now your equation is 4x= $\frac{-1}{8}$ . Next divide both sides by 4 to isolate "x." Now your equation is x= - $\frac{1}{32}$

Hope this helped and have a great day.

(brainliest please)

6 0

2 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: