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3 years ago

Please help me im having a hard time with math

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

4 0

First one is arithmetic sequence in disguise

an=a1+d(n-1)
a1=first term
d=common differce
n=which term
so
first erm is 4
common difference is 9-4=5
an=4+5(n-1)
when n=10
4+5(10-1)
4+5(9)
4+45
49

B
3.5, to 6.5, 9.5
aritmetic, increase by 3, first term is 3.5
an=3.5+3(n-1)
10th term
3.5+3(10-1)
3.5+3(9)
3.5+27
30.5

A is49
B is 30.5
A is answer

an=a1+d(n-1)
115+(-8)(14-1)
115-8(13)
115-104
11
answer is B

an=a1+d(n-1)
45+(-3)(10-1)
45-3(9)
45-27
18

C

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Derivada de un producto Y=x3-8

liubo4ka [24]

Answer:

x = 8/3

Step-by-step explanation:

y = 0

0 = x3 - 8

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4 0

4 years ago

a rectangle has a length of x inches and a width 3 inches less than the length. if the dimensions were doubled , what would be t

iren [92.7K]

Original length: x
original width; x-3
original area: x(x-3)
when the dimensions doubles, that is, increase by a factor of 2, the area increase by 2²
4[x(x-3)]
4x(x-3)=4x²-12x

you can also do it this way:
original length: x doubled: 2x
original width; x-3 doubled: 2(x-3)
new area: 2x[2(x-3)]= 4x²-12x

6 0

4 years ago

Pam jogged up the hill at 6 km/h and then jog down back down the hill at 10 km an hour how many kilometers did you travel at all

atroni [7]

Answer: you travelled 10 km

Step-by-step explanation:

Pam jogged up the hill at 6 km/h.

Let x represent the number of kilometers that you travelled by jogging up the hill or returning back.

Time = Distance/speed

Pam jogged up the hill at 6 km/h.

Time spent in jogging up the hill would be

x /6

She then jog back down the hill at 10 km an hour. Time spent in jogging down the hill would be

x /10

If the total jogging tie is 1 hour 20 minutes, converting to hours, it becomes 1 + 20/60 = 1.33

Therefore

x /6 + x/10 = 1.33

10x + 6x = 80

16x = 80

x = 80/16 = 5

Total distance travelled up and down the hill would b

5 × 2 = 10 km

4 0

4 years ago

Write the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5).

lys-0071 [83]

Answer:

$(x+1)^2 + (y- 3.5)^2 =64$

Step-by-step explanation:

We are given that endpoints of a diameter at the points (7,2) and (-9,5).

Center of the circle is the mid point of diameter

So, first find the mid point of diameter

Formula : $x=\frac{x_1+x_2}{2} , y=\frac{y_1+y_2}{2}$

$(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)$

Substitute the values in formula

$x=\frac{7-9}{2} , y=\frac{2+5}{2}$

$x=-1 , y=3.5$

So, center of circle = (h,k )=(-1,3.5)

To find length of diameter :

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)$

$d=\sqrt{(-9-7)^2+(5-2)^2}$

$d=\sqrt{265}$

Length of radius = r = $\frac{Diameter}{2}=\frac{\sqrt{256}}{2}$

Standard form of the equation of the circle : $(x -h)^2 + (y- k)^2 = r^2$

(h,k )=(-1,3.5)

$r=\frac{\sqrt{256}}{2}$

Equation of the circle : $(x+1)^2 + (y- 3.5)^2 =(\frac{\sqrt{256}}{2})^2$

Equation of the circle : $(x+1)^2 + (y- 3.5)^2 =64$

Hence the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5) is $(x+1)^2 + (y- 3.5)^2 =64$

5 0

4 years ago

Compute 5e2 - 4g + 7 where e = 4 and g = 6 ?

Elza [17]

The value of expression is 63 when e = 4 and g = 6

Solution:

Given expression is:

$5e^2-4g+7$

We have to solve the expression

Given that e = 4 and g = 6

Substitute e = 4 and g = 6 in given expression

$\rightarrow 5(4)^2 -4(6) + 7\\\\Simplify\ the\ above\ equation\\\\\rightarrow 5(16) -24 + 7\\\\\rightarrow 80-24+7\\\\Simplify\\\\\rightarrow 56+7=63$

Thus value of expression is 63

3 0

3 years ago