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VashaNatasha [74]
3 years ago
10

If the perimeter of triangle ABC is 45, what is the perimeter of triangle CRB?

Mathematics
1 answer:
anygoal [31]3 years ago
8 0

Answer:

b. 54

Step-by-step explanation:

45 is original perimeter for ABC. You subtract 16 and 9 from 45 to get the missing side B which is 20. To answer the the perimeter for triangle CRB you add 20 to the other sides which is 15 and 19. The total is 54.

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Which of the following are square roots of the number below? Check all that
julia-pushkina [17]

Answer:

A and D

Step-by-step explanation:

576 ^ 1/2 = + or - 24

3 0
3 years ago
The bakery is selling bagels at a cost of 6 for $7.50. at that rate, how much would 8 bagels cost?
alexira [117]
6:7.50=8:x
6x=7.50*8=60
x=10.00
7 0
3 years ago
What is the result of converting 1250 yards into miles? Remember that 1 mile = 1760 yards.
Kobotan [32]

Answer:

Step-by-step explanation:

1.41

8 0
3 years ago
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°
djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, \angle ABN is 37°. We can see from the diagram that \angle ABC would be 180-37= 143°.

Also, the new bearing is N 25°E. So, \angle BCA would be 25°.

Now we can find \angle BAC. As the sum of the internal angle of a triangle is 180°.

\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is AC=x

We can apply the sine rule now.

\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0
3 years ago
In the diagram,
forsale [732]

Answer:

Probability that the measure of a segment is greater than 3 = 0.6

Step-by-step explanation:

From the given attachment,

AB ≅ BC, AC ≅ CD and AD = 12

Therefore, AC ≅ CD = \frac{1}{2}(\text{AD})

                                  = 6 units

Since AC ≅ CD

AB + BC ≅ CD

2(AB) = 6

AB = 3 units

Now we have measurements of the segments as,

AB = BC = 3 units

AC = CD = 6 units

AD = 12 units

Total number of segments = 5

Length of segments more than 3 = 3

Probability to pick a segment measuring greater than 3,

= \frac{\text{Total number of segments measuring greater than 3}}{Total number of segments}

= \frac{3}{5}

= 0.6

4 0
3 years ago
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