Complete question :
Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this situation?
Answer: Ei = nPi
Step-by-step explanation:
Since Pi represents the probability of observing the ith outcome
The number of independent trials n = k>3 :
Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.
Hence, Expected count (Ei) = probability of ith count * n
Ei = nPi
2y-x=3/4(-y+1)first distribute
2y-x=-3/4y+3/4 get the y on one side
2y-x+3/4y=3/4 add 3/4y to both sides
2y+3/4y=3/4+x add x to both sides
11/4y=3/4+x now divide by 11/4 (both sides)
y=3/11+4/11x
y=3+4x/11
choice c is the answer
Answer:
2x= 3x-7
-x=-7
x=7
so, the first option
Step-by-step explanation:
Carpet Master would be cheaper because 6 x 9 would be 54 $$$
Answer:
So.. I believe the answer is 17
Step-by-step explanation:
In order to get your answer, you would first multiply 38*12 which is 456
Then you would get that number (456) and divide it by 7,752
So 7,752/456 is 17
