Here is your answer and an explanation
Answer: y = -2/3x
Explanation:
This can be determined by calculating the gradient of the straight line, using:
m=ΔyΔx
=−6−34−(−2)
=−96
=−32
Then we use the slope-point form of the straight line:
y−y1=m(x−x1)
to give:
y−3=−32(x−(−2))
∴y−3=−32(x+2)
∴y−3=−32x−3
∴y=−32x
(x+4)^2 / 9 - (y+3)^2 / 16 = 1
a^2 = 16 and b^2 = 9
a = +4 and -4
b = +3 and -3
Center is (-4, -3)
Vertices is (-4 + a, -3) and (-4 - a, -3)
Vertices is (-1, -3) and (-7, -3)
Answer:
Answer would be C.
1 Gallon=3.78
3.78x5
= 18.9
Step-by-step explanation:
Solution: X=6
Detailed explanation:
In this problem we're asked to find "x" or the unknown.
The first step is to subtract 11x from both sides.
Next, subtract 79 from both sides.
To finish this off, divide both sides by -11.
Voila! There's our answer!
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Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.
We then multiply everything together to simplify:
sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes
3x^2 * sin(x^3)/(cos(x^3))^2
and multiplying the constant 7 from the beginning:
7 * 3x^2 = 21x^2, so...
our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2
