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Ostrovityanka [42]
3 years ago
6

At an animal park 2/5 of the animals are felines, and 1/4 of the animals are reptiles. The rest of the animals are aquatic. What

percentage of the animals at the zoo are aquatic?
Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

35%

Step-by-step explanation:

Felines: 2/5 = 40%

Reptiles: 1/4 = 25%

Aquatic: 35%

All you have to do is to first divide the numerator by the denominator. Then multiply it by 100. (or just add the percentages and subtract them from 100%)

Hopefully this helps :3 sorry if wrong :( plz mark brainiest if correct :D Your bootiful/handsome! Have a great day <3

-Bee~

notka56 [123]3 years ago
3 0

Answer:

Felines: 40%

Reptiles: 25%

Aquatic Animals is 35%

Which means the Answer is 35%

(How you do this)

- First, Divide, the Numerator, by the Denominator and multiply it by 100.

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zasha spent $6 on packages of gum.How many more packages of gum that cost $1.20 each can she buy if she has a $20 bill
antiseptic1488 [7]
You have to make an inequality:
1.2x + 6 ≤ 20
       - 6     - 6     isolate x

1.2x ≤ 14
÷1.2     ÷1.2   isolate x

x ≤  11.666

Since you can't buy 2/3 of a pack, she can only buy 11 pieces of gum.

Hope this helps!
4 0
3 years ago
at a concession stand 9 slices of pizza and 5 soft pretzels cost $33.25. If 4 slices of pizza and 6 soft pretzels cost $19.50. W
jok3333 [9.3K]

Answer:

The cost of soft pretzel is $1.25

Step-by-step explanation:

Let $x be the price of one slice of pizza and $y be the price of one soft pretzel.

1. 9 slices of pizza cost $9x and 5 soft pretzels cost $5y. Together they cost $33.25, then

9x+5y=33.25.

2. 4 slices of pizza cost $4x and 6 soft pretzels cost $6y. Together they cost $19.50, then

4x+6y=19.50.

3. Solve the system of two equations:

\left\{\begin{array}{l}9x+5y=33.25\\4x+6y=19.50\end{array}\right..

Multiplythe first equation by 4, the second equation by 9 and subtract them:

4(9x+5y)-9(4x+6y)=4\cdot 33.25-9\cdot 19.50,\\ \\36x+20y-35x-54y=133-175.5,\\ \\-34y=-42.5,\\ \\y=\$1.25.

Then

4x+6\cdot 1.25=19.50,\\ \\4x=19.50-7.50,\\ \\4x=12,\\ \\x=\$3.

6 0
3 years ago
Read 2 more answers
How to Solve 9=m-4<br> And check answer
Natalija [7]
Do 9+4 because you need to get m alone. you get 13 plug 13 in for m (13-4=9) and then 9=9
7 0
3 years ago
A square garden plot measures 180 square feet. A second square garden plot measures 320 square feet. How many more feet of fence
REY [17]

The second garden plot will require 8√5 feet more fence than the first garden plot.

Further explanation:

In order to find the fence, we have to find the perimeter of both squares

So,

Area of Square 1: A1=180 square feet

Area of Square 2: A2=320 Square feet

Let x be the side of square 1:

Then,

A_1=x^2\\180=x^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{180}=\sqrt{x^2}\\x=\sqrt{2*2*3*3*5}\\x=\sqrt{2^2*3^2*5}\\x=2*3\sqrt{5}\\x=6\sqrt{5}

For second square:

Let y be the side of second square

A_2=y^2\\320=y^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{320}=\sqrt{y^2}\\y=\sqrt{2*2*2*2*2*2*5}\\y=\sqrt{2^2*2^2*2^2*5}\\y=2*2*2\sqrt{5}\\y=8\sqrt{5}

Perimeter of First Square:

P_1=4x\\=4(6\sqrt{5})\\=24\sqrt{5}\ feet

Perimeter of Second Square:

P_2=4y\\=4(8\sqrt{5})\\=32\sqrt{5}\ feet

The smaller perimeter will be subtracted from larger perimeter to find that how much more fence will be needed.

P_2-P_1=32\sqrt{5}-24\sqrt{5}\\=(32-24)\sqrt{5}\\=8\sqrt{5}\ feet

The second garden plot will require 8√5 feet more fence than the first garden plot.

Keywords: Radicals, Operations on Radicals

Learn more about radicals at:

  • brainly.com/question/13219835
  • brainly.com/question/1836777

#LearnwithBrainly

6 0
3 years ago
-(3/4)+1 7/8 divided by 1/2 =n
VashaNatasha [74]

first off, let's convert the mixed fraction to improper fraction and then proceed, let's notice that by PEMDAS or order of operations, the multiplication is done first, and then any sums.

\stackrel{mixed}{1\frac{7}{8}}\implies \cfrac{1\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{15}{8}} \\\\[-0.35em] ~\dotfill\\\\ -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \div \cfrac{1}{2}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \cdot \cfrac{2}{1}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{4} \\\\\\ \cfrac{-3+15}{4}\implies \cfrac{12}{4}\implies 3

5 0
2 years ago
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