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zheka24 [161]
4 years ago
15

Solve the equation 3/4=m+1/4

Mathematics
2 answers:
Lana71 [14]4 years ago
7 0

Answer:

m=  

2

1

​  

=0.500

Step-by-step explanation:

spayn [35]4 years ago
4 0

Answer:

1/2 = m

Step-by-step explanation:

3/4=m+1/4

Subtract 1/4 from each side

3/4 - 1/4=m+1/4-1/4

2/4 = m

Simplify

1/2 = m

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Complete the table to show the interest earned for different savings principals, interest rates, time periods.
EastWind [94]

Answer:just multiply your numbers by the interest rates with a decimal point in front.

Step-by-step explanation:

7 0
3 years ago
The perimeter is 40. How much bigger is the longest side than the shortest side?
sesenic [268]

Answer:

10

Step-by-step explanation:

40=2a<u>-3</u>+2a+3a<u>+1</u>

add like terms

  • 40=7a-2

get 'a' by its self

  • 40(+2)=7a<u>-2(+2)</u> [2 cancels out]
  • 42(÷7)=7a(÷7) [7 cancels out]
  • a=6

plug in the answer for Equations

  • biggest: 3(6)+1= 18+1= 19
  • smallest: 2(6)-3= 12-3=9

subtract smallest from biggest

  • 19-9=10

3 0
4 years ago
H - 8 = 2; 28 tell whether the given number is a solution to the equation
murzikaleks [220]
H-8=2. The only solution to that equation is H=10. Any other number isn't.
8 0
3 years ago
-3|9x-7|=2 Find the answer for x
labwork [276]
<h2>Solving Equations with Absolute Expressions</h2><h3>Answer:</h3>

<u>No Solutions</u>

<h3>Step-by-step explanation:</h3>

Given:

-3|9x -7| = 2

Rewriting the given equation:

-3|9x -7| = 2 \\ |9x -7| = -\frac{2}{3}

We have to realize that the right side of the equation, |9x -7|, will always be positive no matter what real values of x (because we're taking the absolute value of the expression) and we are equating it to a <em>negative</em> constant number, -\frac{2}{3}\\. Something that is always positive will never be negative so there's no value for x that satisfies the solution.

\rule{6.5cm}{0.5pt}

<em>You</em><em> </em><em>may</em><em> </em><em>not</em><em> </em><em>read</em><em> </em><em>the</em><em> </em><em>following</em><em> passage</em><em> </em><em>that</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>written.</em>

\rule{6.5cm}{0.5pt}

Solving by positive of the expression:

9x -7 = -\frac{2}{3} \\ 9x = -\frac{2}{3} +7 \\ 9x = -\frac{2}{3} +\frac{21}{3} \\ 9x = \frac{19}{3} \\ 9x \times \frac{1}{9} = \frac{19}{3} \times \frac{1}{9} \\ x = \frac{19}{27}

Solving by the negative of the expression:

-(9x -7)= -\frac{2}{3} \\ 9x -7 = \frac{2}{3} \\  9x = \frac{2}{3} +7 \\ 9x = \frac{2}{3} +\frac{21}{3} \\ 9x = \frac{23}{3} \\ 9x \times \frac{1}{9} = \frac{23}{3} \times \frac{1}{9} \\ x = \frac{23}{27}

Checking: x = \frac{19}{27}\\

-3|9(\frac{19}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|-\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2

x = \frac{19}{27}\\ is an extraneous solution.

Checking: x = \frac{23}{27}\\

-3|9(\frac{23}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2

x = \frac{23}{27}\\ is an extraneous solution.

8 0
3 years ago
How to solve q =r/2(s+t) for t
Lera25 [3.4K]
<span>q =r/2(s+t) for t
</span><span>2q =r(s+t) 
2q = rs + rt
rt = 2q - rs
 t = 2q/r - s
hope it helps</span>
4 0
3 years ago
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