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lubasha [3.4K]
3 years ago
10

PLEASE HELP!! WILL GIVE BRAINIEST!!​

Mathematics
1 answer:
muminat3 years ago
4 0

Answer:

1) c (a,b)

2)The length of DB (I can't put the line on top)

3) AC

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Look at the pic try to show ur work for those equations the best u can I’ll give you the brainly thing who ever does the best
-Dominant- [34]
Alrighty! KFC! Keep, change, flip! When dividing fractions, you keep the first fraction, flip the second, and change the divide sign to multiply. Here is work as requested.
6 0
3 years ago
A population, P(t) (in millions) in year t, increases exponentially. Suppose P(9)=16 and P(18)=24. a) Find a formula for the pop
jenyasd209 [6]

Answer:\frac{32}{3}\left ( 1.0460\right )^t

Step-by-step explanation:

Given

Population changes exponentially

P\left ( t\right )=ab^t

P\left ( 9\right )=16------1

P\left ( 9\right )=16=ab^8

P\left ( 18\right =24=ab^{18}-----2

divide 1 & 2 we get

\frac{24}{16}=\frac{b^{18}}{b^9}

\frac{3}{2}=b^9

Substitute b^9 in 1 we get

a=\frac{32}{3}

Thus P\left ( t\right )=\frac{32}{3}\left ( 1.0460\right )^t

8 0
3 years ago
Read 2 more answers
3. Formulate 900 lbs of a 35% CP ration using Soybean Meal (46% CP) and Oats (12% CP). How many pounds of soybean meal will be u
Anarel [89]

Answer:

The amount of Soyabean = 608.82 pounds.

The amount of Oats  = 900-608.82 = 291.18 pounds.

Step-by-step explanation:

Given that the Soybean Meal has 46% CP and Oats has 12% CP.

The total amount of ration is 900 lbs of 35% CP.

Let x pounds of Soyabean has been used, so,

the amount of Oats = 900-x lbs.

The CP amount in 900 lbs mixture will be equal to the sum of CP amounts in x lbs Soyabean and 900-x lbs Oats, i.e

35% of 900 = 46% of x + 12% of (900-x)

\Rightarrow \frac{35}{100}\times 900=\frac{46}{100}\times x+\frac{12}{100}\times (900-x)

\Rightarrow  35\times 900 = 46x + 12\times 900 - 12 x

\Rightarrow 34x= 900(35-12)

\Rightarrow x = (900\times 23)/34

\Rightarrow x = 608.82 lbs.

So, the amount of Soyabean = 608.82 pounds.

The amount of Oats  = 900-608.82 = 291.18 pounds.

5 0
2 years ago
A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust
AlexFokin [52]

Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let <em>X</em> = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts <em>n</em> = 8 potential customers per day.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

E(X)=np=8\times 0.10=0.80

Thus, the expected number of sales per day is 0.80.

7 0
3 years ago
the temperature ,t, in Burrtown starts at 21 degrees F at midnight, when h=0. For the next few hours, the temperature drops 4 de
lbvjy [14]

the temperature ,t, in Burrtown starts at 21 degrees F at midnight, when h=0. For the next few hours, the temperature drops 4 degrees every hour. which equation represents the temperature ,t, at hour h?

t =21-4h


7 0
3 years ago
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