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Vilka [71]
3 years ago
7

How do you solve (5^{2} - 1) ÷ 6

Mathematics
2 answers:
posledela3 years ago
8 0

( {5}^{2}  - 1) \div 6 =

(25 - 1) \div 6 =

24 \div 6 = 4

Note:

Do the square first, and then you do mathematic operation between the parentheses. And, then do the

mathematic operation in the outside of parentheses.

Thank you.

Anarel [89]3 years ago
6 0

Answer:

<h2>4</h2>

Step-by-step explanation:

\left(5^2-1\right)\div \:6\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(5^2-1\right)\::\quad 24\\=24\div \:6\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:24\div \:6\:\\:\quad 4

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