Answer: If you're looking for the value of x, it's 1.
Step-by-step explanation:
Add the numbers. x-10-2x+7=8+x-10-3x--->x-3-2x=8+x-10-3x
Combine like terms. x-3-2x=8+x-10-3x ---> -x-3=8+x-10-3x
Subtract the numbers.-x-3=8+x-10-3x---> -x-3=-2+x-3x
Combine like terms. -x-3=-2+-3x---> -x-3=-2-2x
Rearrange terms. -x-3=-2-2x---> -x-3=-2x-2
Hope that helps!
Answer:
a vertical shift of f, c units down
Step-by-step explanation:
Given:
- A function h(x) is defined as:
h(x) = f(x) − c
Find:
- The effect of "c" on the f(x) function.
Solution:
- The effect of adding or subtracting any constant to or from a given function f(x) shifts the f(x) value for all values of x by an amount "c"
- This effect can be modeled on a graph by a "vertical shift" i.e there is an increase/decrease in every "y" value by amount "c" units.
- In the case given we see that "c" units have been subtracted from original f(x).
- Meaning, all f(x) values have decreased for every value of x. This can be categorized as vertical shift of f(x) with "c" units down.
This is not my answer, someone else answered this question before.
red:green
5:3
5+3=8
8 units
4qt=8 units
divide by 8
0.5qt=1unit
5 unit=red
5*0.5=2.5qt, red=2.5qt
3unit=lime
0.5*3=1.5qt
1.5qt, 2/3 of that is yellow, 1/3 is blue, 1.5 times 2/3=1, 1.5 times 1/3=0.5
result:
2.5qt red
1qt yellow
0.5qt blue
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
Answer:
3 cans of white paint
Step-by-step explanation:
.25white xwhite
_______=_______
.50blue 6blue
cross multiply .50x =1.5
divide by .50
and x = 3
