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wolverine [178]

3 years ago

14

Evaluate |3 - 5 + 7|. -5 5 -15 15

1 answer:

Mnenie [13.5K]3 years ago

7 0

The right answer is 5

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The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial

GREYUIT [131]

Answer:

P(0) = 7,917

Step-by-step explanation:

The population of the community is given by the following formula:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the initial population and r is the growth rate.

The initial population P0 has doubled in 5 years.

This means that

$P(5) = 2P(0)$

Which lets us find r.

$P(t) = P(0)(1+r)^{t}$

$2P(0) = P(0)(1+r)^{5}$

$(1+r)^{5} = 2$

Applying the 5th root to both sides

$1+r = 1.1487$

$r = 0.1487$

So

$P(t) = P(0)(1.1487)^{t}$

Suppose it is known that the population is 12,000 after 3 years.

With this, we find P(0)

$P(t) = P(0)(1.1487)^{t}$

$12000 = P(0)(1.1487)^{3}$

$1.5157P(0) = 12000$

$P(0) = \frac{12000}{1.5157}$

$P(0) = 7917$

4 0

2 years ago

Joy bought 2 bath towels from a linen store, but returned 3 hand towels. Kay bought 3 bath towels and 3 hand towels. Joy's bill

nevsk [136]

Answer:

Bath towels: $10 Hand towels: $5

Step-by-step explanation:

If Joy bought two bath towels, that are $10 each that's $20 total; but she returned 3 hand towels that cost $5 and $15 total. 20-15=5

3 0

3 years ago

ABCD Is a parallelogram if m

Viefleur [7K]

Step-by-step explanation:

ABC+DAB=180

DAB=180-115

DAB= 65

m<3+m<4=65

m<3=65-m<4

You have been given 4 degrees there, but it has not fallen. The answer is either A or B. Subtracting the conditional degree from 65. Find 3.

7 0

2 years ago

Read 2 more answers

In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo

Scorpion4ik [409]

Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

we have

$A=17\ cm^2$

$AB=(3x-2)\ cm$

$BC=(x+3)\ cm$

substitute the values

$17=\frac{1}{2}(3x-2)(x+3)$

$34=(3x-2)(x+3)$

$34=3x^2+9x-2x-6$

$3x^2+7x-6-34=0$

$3x^2+7x-40=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2+7x-40=0$

so

$a=3\\b=7\\c=-40$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

$x=\frac{-7(+/-)\sqrt{529}} {6}$

$x=\frac{-7(+/-)23} {6}$

$x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}$

$x=\frac{-7(-)23} {6}=-5$

therefore

The solution is

$x=\frac{8}{3}\ cm$

6 0

2 years ago

-3c=15 c = __ help plz

LuckyWell [14K]

You would divide negative 3 (-3) from both sides to keep the c by itself. When you divide a positive by a negative it becomes negative.

Dividing 15 by -3 would equal -5, so c = -5

7 0

3 years ago