Answer: < n <
<u>Step-by-step explanation:</u>
| 3n - 2 | - 2 < 1
<u> +2 </u> <u>+2 </u>
| 3n - 2 | < 3
3n - 2 < 3 and 3n - 2 > -3
<u> +2 </u> <u>+2 </u> <u> +2 </u> <u> +2 </u>
3n < 5 and 3n > -1
n < and n >
< n <
Interval Notation:
Graph: o--------------------o
Answer:
Required probability is 0.784 .
Step-by-step explanation:
We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.
Let Probability that the students passed the first exam = P(F) = 0.74
Probability that the students passed the second exam = P(S) = 0.72
Probability that the students passed both exams = = 0.58
Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;
As we know that conditional probability, P(A/B) =
Similarly, P(S/F) = =
{As
is same as
}
= = 0.784
Therefore, probability that he passed the second exam is 0.784 .