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3 years ago

PLEASE HELP WITH THIS CONDITIONAL PROBABILITY QUESTION AND PLEAS COULD YOU SHOW A STEP BY STEP EXPLANATION.

1 answer:

5 0

Hello I know this may be difficult on your end but you don’t always have to get the answer from someone you can contact a teacher and get help this keep be very helpful keep this in your head you are intelligent no matter what anyone tells you ask your teacher a question about the problem tell them you don’t get how to do it if you have to just whatever it takes for you to learn how to do it have a wonderful day or night bye!!!...

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7. John worked 32 hours last week and 28 hours this week. If he gets paid

AlladinOne [14]

Answer:

$630

Step-by-step explanation:

week 1 : $336

week 2 : $294

gross pay : $630

6 0

3 years ago

The volume of a square prism is 144x^3 +216x^2 +81x

Svetach [21]

Answer:

Equation for the perimeter of prism's square face: 16x + 12

Step-by-step explanation:

Volume of Square prism = Length * Width * Height

= 144 x^3 + 216 x^2 +81 x

taking 9x common = 9x( 16 x^2 + 24 x + 9)

= 9x ( (4x)^2 + 2(4x)(3) + (3)^2 )

= 9x ( 4x+3)^2

so the length is 9x, width is 4x+3 and height is 4x+3

Now, Perimeter of prism's square face = 2* Width + 2 * Height

= 2* (4x+3) + 2* (4x+3)

= 8x +6 + 8x + 6

= 16x +12

6 0

3 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

4 years ago

Please help me figure this out!!!!!!

Firdavs [7]

The answer is 129.13 is your answer. Remember, the perimeter of the base is 4s since it is a square. There is no formula for a surface area of a non-regular pyramid since slant height is not defined. To find the area, find the area of each face and the area of the base and add them.

8 0

4 years ago

Read 2 more answers

Explain the steps of adding decimals

faltersainse [42]

Line the decimal points up. Then add like you normally would, but put down the decimal directly where you have it lined up.

4 0

3 years ago