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Anon25 [30]
3 years ago
14

Please help me solve for 3,4,and 5 please!

Mathematics
1 answer:
Nikolay [14]3 years ago
7 0

Answer:

solved!

Step-by-step explanation:

https://drive.google.com/open?id=1QAvmjDjuwgFX0mUdHlWmqMSCJcOVMw2X

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Thomas has $6.35 in dimes and quarters. The number of dimes is three more than three times the number of quarters. How many quar
mr Goodwill [35]

Answer:

He has 11 quarters

Step-by-step explanation:

* Lets study the information in the problem to solve it

- The value of dimes and quarters is $6.35

- There are dimes and quarters

- The dime = 10 cents

- The quarter = 25 cents

* We must change the money from dollars to cents

∵ $1 = 100 cents

∴ $6.35 = 6.35 × 100 = 635 cents

- The number of dimes = 3 + 3 × number of quarters

* Let number of dimes is D and number of quarter is Q

∴ D = 3 + 3Q

∴ 10D + 25Q = 635

* Substitute the value of D from first equation in the second equation

∴ 10(3 + 3Q) + 25Q = 635 ⇒ open the bracket

∴ 10(3) + 10(3Q) + 25Q = 635

∴ 30 + 30Q + 25Q = 635 ⇒ collect like terms

∴ 30 + 55Q = 635 ⇒ subtract 30 from both sides

∴ 55Q = 605 ⇒ divide both sides by 55

∴ Q = 11

* He has 11 quarters

5 0
3 years ago
Adam went to McDonald's and bought a Big Mac and 2 small fries. Adam spent
Rudiy27

Answer:

the answer is 4.94 because you subtract 10.93-5.99

3 0
2 years ago
Megan has a pen for her dog the dimensions of the pen are in meters
Alex73 [517]
So measure the pen in meters
3 0
3 years ago
What type of number is 10.9+3i?
hram777 [196]

Answer:

I think its a rational number

Step-by-step explanation:

3 0
2 years ago
Airen’s grandparents deposited $1300 in a mutual fund earning 6% interest compounded annually. Write an equation to represent ho
IRINA_888 [86]

~~~~~~ \textit{Compound Interest Earned Amount \underline{in 18 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1300\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &18 \end{cases}

A=1300\left(1+\frac{0.06}{1}\right)^{1\cdot 18}\implies A=1300(1.06)^{18}\implies A\approx 3710.64 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y = 1300(1.06)^x~\hfill

7 0
2 years ago
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