Wat r u asking about this problem
Answer:
There was a 1.93% probability of having multiples (twins or more) in 1980.
Step-by-step explanation:
There were 3,612,258 births in the US in 1980.
Of those,
68339 + 1337 = 69676 were multiplies.
So
What was the probability of having multiples (twins or more) in 1980?
There was a 1.93% probability of having multiples (twins or more) in 1980.
Answer:
Step-by-step explanation:
∛-64 = -4
![\sqrt[3]{m^{15}} =m^5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bm%5E%7B15%7D%7D%20%3Dm%5E5)
∛n³ = <em>n</em>
Answer:
15000(1.003425)^12t ;
4.11%
4.188%
Step-by-step explanation:
Given that:
Loan amount = principal = $15000
Interest rate, r = 4.11% = 0.0411
n = number of times compounded per period, monthly = 12 (number of months in a year)
Total amount, F owed, after t years in college ;
F(t) = P(1 + r/n)^nt
F(t) = 15000(1 + 0.0411/12)^12t
F(t) = 15000(1.003425)^12t
2.) The annual percentage rate is the interest rate without compounding = 4.11%
3.)
The APY
APY = (1 + APR/n)^n - 1
APY = (1 + 0.0411/12)^12 - 1
APY = (1.003425)^12 - 1
APY = 1.04188 - 1
APY = 0.04188
APY = 0.04188 * 100% = 4.188%
5 7/8 is 47/8
Because,
You multiply 5 and 8 and then add 7, then you keep the denominator.
