Please help with this question

Mathematics

1 answer:

BartSMP [9]2 years ago

6 0

X/(x^2+3x+2) - 1/((x+2)(x+1))
x/(x^2+3x+2) - 1/(x^2+3x+2)
(x - 1)/(x^2+3x+2)

Answer: Choice D

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How do I do this qn?

denis-greek [22]

You can take the log of the left and right hand side, and then apply the <span>logarithm rules:

log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)

log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)

simplifying by writing log9 = 2log3 and log6 = log2+log3

x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) =
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So 6^x = 4/9

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2 years ago

hình thang cân abcd ab//cd) đáy lớn = 2,7cm .cạnh bên dài 1cm, góc adc=60 độ . kẻ ae//bc. tính độ dài ab

Olenka [21]

Answer: Is this english or gibberish?

Step-by-step explanation:

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1 year ago

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uysha [10]

Answer: distance from earth to moon is 4x10^5= 4,000,000

The distance from Earth to Mars is about 5x10^7= 50,000,000.

Step-by-step explanation:

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postnew [5]

Answer: $\frac{485}{ 1,454}$

Step-by-step explanation:

For this exercuse you need to analize the information provided. You know that:

1) The height of the replica of the Empire State Building with its antenna spire in Las Vegas is 485 feet.

2) The height of the real Empire State building is 1,454 feet.

Finally, in order to find the ratio of height of the replica to the height of the real Empire State building, its necessary to divide the height of the replica of the Empire State Building by the height of the real Empire State building.

Therefore, trough this procedure you get that the ratio of height of the replica to the height of the real Empire State building is:

$ratio=\frac{heigth_{ replica}}{heigth_{real}}=\frac{485}{ 1,454}$

(This fraction cannot be reduced)

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hammer [34]

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