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3 years ago

15

Ritu started a business and borrowed a certain sum at 14% per annum for 1 year, the interest being compounded semi annually. If

she cleared the account by paying ₹1831.84 after one year, find the sum borrowed by ritu

1 answer:

liubo4ka [24]3 years ago

5 0

Use the formula A = p( 1 + x)^n.

A = 1831.84(1 + 0.14)^6

You can finish.

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20% of a is 11. What is a?

Reika [66]

Answer:

a=55

Step-by-step explanation:

This question is asking for you to find the whole (a), given a part (11). This can be done through multiplication. 20% is 1/5 of 100%. This means to find the whole number, you should multiply the part by 5. 11*5=55. So, a must equal 55.

We can check this answer by working backward. Do this by finding 20% of 55, and checking to see if it is 11. To find a percentage of a number, multiply that number by the percent in decimal form. So, 20% of 55 is equal to 0.2*55, which is 11. Therefore, the answer is correct.

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2 years ago

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Martina begins a dive at sea level. She dives down 20 feet, and then rises 7 feet.

klasskru [66]

Answer:

martina is 22 feet below sea level

Step-by-step explanation:

Marina goes down 20 feet

then rises 7 feet which is 20 - 7 = 13

then goes down 9 more feet which is 13 + 9 = 22 feet

20 - 7 + 9 =22

Martina is 22 feet below sea level.

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2 years ago

A random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength

irinina [24]

Answer:

Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.

Step-by-step explanation:

We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.

<u><em>Let </em></u> $\bar X$ <u><em> = sample mean comprehensive strength</em></u>

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean comprehensive strength = 5500 psi

$\sigma$ = standard deviation = 100 psi

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P( $\bar X$ > 4985 psi)

P( $\bar X$ > 4985 psi) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{4985-5500}{\frac{100}{\sqrt{9} } }$ ) = P(Z > -15.45) = P(Z < 15.45)

= <u>0.99999</u>

<em>Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.</em>

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3 years ago

Winning the jackpot in a particular lottery requires that you select the correct four numbers between 1 and 42 and, in a separa

NARA [144]

Answer:

$\dfrac{1}{3,357,900}$

Step-by-step explanation:

There are

$C^{42}_4=\dfrac{42!}{4!(42-4)!}=\dfrac{42!}{4!\cdot 38!}=\dfrac{38!\cdot 39\cdot 40\cdot 41\cdot 42}{2\cdot 3\cdot 4\cdot 38!}=39\cdot 10\cdot 41\cdot 7=111,930$

different ways to select the four numbers between 1 and 42. Only one of this ways is correct (successful to win).

There are 30 different ways select the single number between 1 and 30. Only one of them is correct.

The probability of winning the jackpot is

$\dfrac{1}{111,930}\cdot \dfrac{1}{30}=\dfrac{1}{3,357,900}$

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Raphael is enrolled as a foreign exchange student. He is from Canada and is going to attend school in Texas. His mother sent him

natita [175]

I pretty sure it would be 609.76

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