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3 years ago

10

Kevin is making a banner with area of 7 square ft width and length of banner is whole numbers what numbers are possible dimensio

ns?

1 answer:

stepladder [879]3 years ago

3 0

Answer:

Length = 7, width = 1.

Step-by-step explanation:

7 and 1 are the only possible dimensions as 7 is a prime number.

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Quadrilateral ABCD is inscribed in a circle.

Lerok [7]

In general, the sum of the measures of the interior angles of a quadrilateral is 360. This is true for every quadrilateral. This does not help here, because there are two angles (angles B and D) we know nothing about. We only know about opposite angles A and C.

In this case, you can use another theorem.
Opposite angles of an inscribed quadrilateral are supplementary.

m<A + m<C = 180

3x + 6 + x + 2 = 180

4x + 8 = 180

4x = 172

x = 43

m<A = 3x + 6 = 3(43) + 6 = 135

Answer: 135 deg

6 0

3 years ago

Find the area of the shape .

weqwewe [10]

Answer:

3.14

Step-by-step explanation:

A=π*r^2

3.14*(2^2)

3.14*4

12.56/4 (because it's 1/4th a circle)

3.14.

3 0

3 years ago

Read 2 more answers

Pls answer 2 people or more

fredd [130]

I believe it’s B . Not 100 percent sure but yeah

6 0

2 years ago

Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.

borishaifa [10]

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 14, p = 0.8$

P(x>10)

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501$

$P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501$

$P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539$

$P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440$

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981$

So P(x > 10) = 0.6981.

8 0

3 years ago

What is 3·3÷3·1²·5 and for any body who doesn't get it Ur not dumb lol

r-ruslan [8.4K]

I'll give you a hint. <u><em>This questions is about order of operations for pemdas. Its stand for: p-parenthesis, e-exponents, m-multiply, d-divide, a-add and s-subtract that came from left to right.</em></u>

First you had to calculate with exponents first.

$1^2=1*1=1$

$3*3/3*1*5$

Then you multiply and divide from left to right.

$3*3=9$

$9/3*1*5$

$3*1*5$

$3*5$

$=15$

Final answer: $\boxed{=15}$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

7 0

3 years ago

Read 2 more answers