1 hour = 60 minutes = 3600 seconds = 1/24 day
Divide every number above by 2 to get 1/2 hour and its equivalent numbers.
1/2 hour = 30 minutes = 1800 seconds = 1/12 day
Answer:
f(g(3)) = 3
Step-by-step explanation:
We are told to solve for f(g(3)). This is also saying f of g of 3.
To find f(g(3)), we need to plug 3 in for x in g(x), since it says g(3).
g(x) = 3(3) - 4
Solve.
= 9 - 4
g(x) = 5
Now, we plug that into f(x), because g(x) was placed inside f and replaces the x variable of f(x).
f(5) = 2(5) - 7
Solve.
= 10 - 7
f(5) = 3.
f(g(3)) = 3
#teamtrees #WAP (Water And Plant)
Answer:
Following are the solution to this question:
Step-by-step explanation:
Using formula:

In question (1):

In point a:

In point b:


In question (2):

In point a:

In point b:


The 3 question is incomplete, that's why it can't be solved.
Answer:
Part a): 100 degrees
Part b): Isosceles Triangle
Step-by-step explanation:
Part a): Since the angle measures of all triangles add up to 180 degrees and since the other two angles are 40 degrees, which add up to 80, we can use subtraction to find the answer.
180 - 80 = 100
Part b): Since only two of the three angles in this triangle have the same measure, we can find that it is an isosceles triangle, with base angles measuring 40 degrees, and the vertex angle being 100 degrees.
Given that X <span>be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.
The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02
Part A:
</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:
</span>

<span>
Part B:
The mean of a binomial distribution is given by
</span>

<span>
The standard deviation is given by:
</span>

<span>
Part C:
This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>