If C is between A and B, then, we can write the equation

Substitute the value of AB and the expressions for AC and CB in terms of x.

We can now solve for x.


Dividing by 5.








(Hard) A composite number n is called a Carmichael number bn−1 ≡ 1 (mod n) for every number b such ... Base case: When n = 2 the formula a + c ≡ b + d (mod m) was already given. ... The sequence goes 1, 3, 7, 15, 31,... guess that it is equal to 2n+1 − 1. ... Prove (now using induction on n) that fm|fmn for all n ≥ 1.
The answer for "-2a + 3b" is 5.
To solve this equation, you must first find "a" and "b". A^3 times B^2 = 72. In this case, a = 2 (2*2*2 = 8) and b = 3 (3*3 = 9) since their outcomes multiplied together equal 72.
Now you fill in for "a" and "b". "-2*2 + 3*3" before adding you do all the multiplying, which leaves "-4 + 9". Combining like terms gives you 5.
I hope this helps!!
To solve this problem, you would divide the total number of newspapers by the amount of newspapers per box, in order to find the number of boxes.
150/10=15.
There would be 15 boxes.
Answer and Step-by-step explanation:
I will be using Desmos to show you the graph.
So, draw your line from the equation, and then lightly shade the left and ride side. That middle side is where there is no solutions for -3 ≤ x ≤ -5 for y = 2x - 5.
The parts that are shaded have the solutions.
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