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Snowcat [4.5K]
3 years ago
6

Graph the image of △UVW after a reflection over the line y=-x

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Rule: (x, y) → (-y, -x)

This means that the x, will now become y, and the y will now become x.

U (-7, -4) → (4, 7)

V (1, -4) → (4, -1)

W (-5, -9) → (9, 5)

U' (4, 7)

V' (4, -1)

W' (9, 5)

*View the attached graph*

  • Yellow is the original figure
  • Purple is the figure after a reflection over the line y=-x

Hope this helps!

aliya0001 [1]3 years ago
4 0

Answer:

9514 1404 393

see attached

Step-by-step explanation:

Reflection over the line x = -1 alters the x-coordinates, but leaves the y-coordinates alone. The image point is as far horizontally from the reflection line as the pre-image point is. Each new x-coordinate is the old one subtracted from twice the x-value of the line of reflection: (x, y) ⇒ (-2-x, y) U(-8, -6) ⇒ U'(6, -6) V(-3, -6) ⇒ V'(1, -6) W(-4, -1) ⇒ W'(2, -1)

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Using the graph as your guide, complete the following statement.
ollegr [7]

Answer:

positive

Step-by-step explanation:

the discriminant of the function is postive.

because from the graph we notice that it has 2 intercepts on x-axis, which means the function has 2 real solution when y=0

that implies the discriminant is positive.

\Delta = \sqrt{b^2-4ac}

if \Delta > 0 we have 2 distinct real solution

if \Delta we have no real solution but 2 complex solutions

if \Delta = 0 we have 2 identical real solution

7 0
3 years ago
1 15/100 +1/50 +1.175
kifflom [539]
Convert all into a fraction and you will get 115/100+1/50+47/40
So your answer is 469/200 or 2.345 as a decimal
4 0
4 years ago
Read 2 more answers
XD Plzzzzzz do 2 slides (4 problems)
Leya [2.2K]

Answer:

Slide 1:

1. Solution = (-3,2)

<em>y = 2x - 1</em>

<em>y = 3/2x + 6</em>

2. No solution

<em>y = -4/2x + 4</em>

<em>y = -4/2x - 5</em>

Slide 2:

3. Solution = (1, -6) ONE SOLUTION

4. Solution = (-4, -1) ONE SOLUTION

p.s i attached the graphs for problems 3 and 4. The first picture is for problem 3 and the second picture is for problem 4

I really hope this helped :)

6 0
3 years ago
Can someone help me with this
mash [69]

The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

d =  \sqrt{(x1 - x2) {}^{2}  +  {(y1 - y2)}^{2} }  \\ r =  \sqrt{ {( - 2 - 0)}^{2} +  {( - 3 - ( - 3))}^{2}  }  \\ r =  \sqrt{ {( - 2)}^{2} +  {( - 3 + 3)}^{2}  }  \\ r =  \sqrt{ {4}^{2} + 0 }  \\ r =  \sqrt{4}  \\ r = 2

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

(x - h) {}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

{(x - ( - 2))}^{2}  +  {(y - ( - 3))}^{2} =  {r}^{2}

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

Learn more about circle, refer:

brainly.com/question/24810873

#SPJ9

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2 years ago
Simplifying square root
oee [108]
Answer is A. 6
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3 years ago
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