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Daniel [21]
2 years ago
12

3 = t + 11.5 - t

Mathematics
1 answer:
Ray Of Light [21]2 years ago
8 0

Answer:

There are no solutions.

Step-by-step explanation:

3=t+11.5-t

3=11.5 (does not work)

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A hope this helps :)
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3 years ago
Find the area of the largest rectangle (with sides parallel to the coordinate axes) that can be inscribed in the region enclosed
garik1379 [7]
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards. 
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards. 
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Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
 => Area, A 
= 2x (y1 - y2) 
= 2x (18 - x^2 - 2x^2 + 9) 
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For area to be maximum, dA/dx = 0 and d²A/dx² < 0 
=> 54 - 18x^2 = 0 
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants) 

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=> maximum area 
= 54(√3) - 6(√3)^3 
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4 0
3 years ago
Solve for X using either sine, cosine, or tangent
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Answer:

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Step-by-step explanation:

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x=14√3 *Sin30

x=7√3

x=12.12

•Tan30°=6√3÷x

x=6√30 ÷Tan 30

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x=56.92

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3 years ago
CORRECT ANSWER WILL GET BRAINLIEST. 30 points!
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The answer is c i think
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Answer:

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Step-by-step explanation:

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3 years ago
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