She practices for 40 minutes on Monday.
On Tuesday she practices for 5/8 of 40 minutes.
On Tuesday she practices for 25 minutes.
On Wednesday she practices for 4/5 of 25 minutes.
Hannah practices for
A. 20 minutes on Wednesday.
If you can graph a function, you can graph piecewise functions. Each one of them is a different line or curve within the domain for that specific line of curve. If the domain states it's less than or greater than a number, you circle that point on the line. If the domain states it's also possibly equal to the point at the beginning or the end, you make a closed dot.
I"m sure that's clear as mud, please respond with any additional questions.
Answer:
Peter's number is 36.
Step-by-step explanation:
If you subtratct 13 from 36, you get 23.
If you multiply that times -3, you get -69.
(The way I got 23 was by dividing -69 and -3)
I hope this helped you even though it's late.
Answer:
5 solutions.
x=0
x=0
x=0
x=1
x=-1
Step-by-step explanation:
To solve this, we need to handle the radical function somehow, an easy approach is to raise to square power the whole equation, this way you can get rid of it.
sqr( x^(3/2) = x^(5/2) )=
x^3 = x^5
Now, lets group terms
x^5-x^3==0
GCF x^3
x^3(x^2-1)=0
The above equation gives us already 5 answer
In order to satisfy the equation there are two choices:
x^3=0 (a)
or (x^2-1)=0 (b)
From (a), we have that x=0, thus given one solution from here.
However, the amount of solutions is not just one, its 3, because the amount of solutions is linked to the exponent of the variable.
the other equation (b)
gives us x =sqrt(1), leading to x= -1 or x=+1
We have two solutions here, again, the exponent of the variable already tells us the amount of solutions,