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3 years ago

Julie works in a leisure centre. Part of her duties is to prepare personal fitness plans for her clients.

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

8 0

Answer:

Janelle is applying to work a full-time job next summer. So far, her only paid work experience has involved with babysitting. She's worried that she lacks the skills

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1/2r + 2(3/4r - 1) = 1/4r + 6

taurus [48]

$\frac{1}{2}r+2(\frac{3}{4}r-1)=\frac{1}{4}r+6\ \ \ \ \ \ \ |omit\ bracket\\\\\frac{1}{2}r+\frac{3}{2}r-2=\frac{1}{4}r+6\ \ \ \ \ \ |\cdot4\\\\2r+6r-8=r+24\ \ \ \ \ \ |combine\ like\ terms\\\\2r+6r-r=24+8\ \ \ \ \ |simplify\\\\7r=32\ \ \ \ \ |:7\\\\r=\frac{32}{7}=4\frac{4}{7}$

3 0

3 years ago

Read 2 more answers

If MN > LP, then 2 _____ 3. Choose the relationship symbol to make a true statement.

Mumz [18]

Then 2 is greater than 3 (>)

6 0

3 years ago

Which value of x is in the solution set of the following inequality. -3x +5 >7

Vadim26 [7]

I’m not sure if this was a typo, but A and B are the same answer. A and B are correct, because when you solve this the answer has to be anything less than -0.6.

8 0

4 years ago

The sequence 2, 3, 5, 6, 7, 10, 11, $\ldots$ contains all the positive integers from least to greatest that are neither squares

sergeinik [125]

The 400th term is 425.

There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are $\lfloor\sqrt[6]{427}\rfloor=2$ numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 = 425.

7 0

3 years ago

find the gradient of the line joining (3,7) and (6,9). Hence, find the acute angle it makes with the positive x-y axis

stiv31 [10]

Answer:

33.7 degrees

Step-by-step explanation:

As we go from (3,7) to (6,9), x increases by 3 and y increases by 2. Thus, the gradient (slope) of the line connecting these two points is

m = rise / run = 2/3. Using the slope-intercept formula y = mx + b, we obtain

7 = (2/3)(3) + b, or 7 = 2 + b, so we see that b = 5 and y = (2/3)x + 5. The y-intercept is (0, 5).

Next we find the x-intercept. We set y = (2/3)x + 5 = to 0 and solve for x:

(2/3)x = -5, or (3/2)(2/3)x = -5(3/2), or x = -15/2, so that the x-intercept is

(-15/2, 0). This line intersects the x-axis at (-15/2, 0).

Now look at the segment of this line connecting (-15/2, 0) and (0, 5). Here x increases by 15/2 and y increases by 5, and so the tangent of the acute angle in question is

tan Ф = 5 / (15/2) = 10 / 15 = 2/3.

Using the inverse tangent function, we get Ф = arctan 2/3, or approx.

33.7 degrees.

I believe you meant "the acute angle it makes with the positive x-axis."

3 0

3 years ago