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kolezko [41]
2 years ago
6

Help me solve this question for geometry and thanks !!

Mathematics
1 answer:
Degger [83]2 years ago
4 0

Answer:

(-2, -6)

Step-by-step explanation:

g(x) = (x+2)²-6

= x²+4x+4-6

= x²+4x-3

the vertex :

x = -4/2 = -2

y = (-2+2)²-6 =0-6 = -6

point of vertex : (-2, -6)

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For the real-valued functions f(x)=2x+1 and g(x)=sqrt(x-1), find the composition f o g and specify its domain using interval not
Anettt [7]

Answer:

fog = 2√(x-1) + 1

Domain = [1, \infty)

Step-by-step explanation:

Given the functions  f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog

fog = f(g(x))

f(g(x)) = f(√(x-1))

f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)

f(√(x-1)) = 2(√(x-1))+1

f(√(x+1)) = 2√(x-1) + 1

fog = 2√(x-1) + 1

<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>

If x-1≥0

x≥0+1

x≥1

This means the range of variable x must be values of x greater than or equal to 1.

Domain = [1, \infty)

8 0
3 years ago
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mars1129 [50]
The answer to this is a=3
4 0
2 years ago
The function f(x) = -6x. The graph of g(x) is f(x)vertically stretched by a factor of 7 and reflected in the x-axis. What is the
Vera_Pavlovna [14]

we are given a function

f(x)=-6x

First translation:

The graph of function  is  vertically stretched by a factor of 7

Whenever we vertically stretch any function  by 'a' units

so, we can write it as

g(x)=a\times f(x)

Here, it is vertically stretch by 7

so, we get

g(x)=7\times -6x

g(x)=-42x

Second translation:

Whenever we reflect  any function  about x-axis

we multiply y-value by -1

so, we can write it as

g(x)=-f(x)

Here , it is reflected in the x-axis

so, we can multiply by -1 to y-value

we get

g(x)=-1\times -42x

g(x)=42x.............Answer


3 0
3 years ago
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Llana [10]
There is no solution
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3 years ago
How many digits are written when 1000 to the power of 2015 is expressed as a numeral?
PtichkaEL [24]

Answer: There are 6046 digits will be written on expansion upto 2015th power.

Step-by-step explanation:

Since we have given that

1000^{2015}

We have to find the number of digits ,

So,

1000^{2015}\\\\=(10^3)^{2015}\\\\=10^{6045}

Since we know that

10^n\text{ has n+1 number of digits }

so,

10^{6045}\text{ has 6046 number of digits }

Hence, there are 6046 digits will be written on expansion upto 2015th power.

6 0
2 years ago
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